實(shí)課程名稱實(shí)驗(yàn)名稱實(shí)驗(yàn)類型集美大學(xué)實(shí)課程名稱實(shí)驗(yàn)名稱實(shí)驗(yàn)類型計(jì)算機(jī)工程學(xué)院驗(yàn)T艮告匯編語言程序設(shè)計(jì)上機(jī)過程及DEBUG命令的使5設(shè)計(jì)型一姓名湯志敏學(xué)號(hào)日期2023.3.30地點(diǎn)陸大208成績(jī)教師呂俊音MOVBL,XCMPBL.YJBL1MOVBL,YL1：CMPBLNJBU2MOVBLN：三個(gè)數(shù)匕匕簌■.司加/J傕核值詒'BLLEASI,WMOV[SI+2],BLL2：MOVBH,BLANDBH.OFOHMOVCL,4RORBH.CLMOVDUBHADDDL,30HMOVAH.O2HINT21H;區(qū)三十色敢ANDBL.OFHCMPBL.O9HJBEL3ADDBL,07HL3：MOVDL,BLADDDU30HMOVAH.02HINT21H:區(qū)3個(gè)臺(tái)酸MOVAH.4CHINT21HCODESENDSENDSTART實(shí)驗(yàn)1.2：DATASSEGMENT:此處筋人教就/代蝎RESULTDB?DATASENDSSTACKS5EGMENT:此處錨人修枝鍛代點(diǎn)STACKSENDSCODESSEGMENTASSUMECS：CODES.DS：DATAS,SS：STACKS5TART：MOVAX.DATASMOVDS,AX;此處觴人代點(diǎn)做代點(diǎn)MOVAH,01HINT21HMOVBL.ALMOVDU,'+'MOVAH.02HINT21HMOVAH,01HINT21HADDBL,ALMOVRESULT.BLSUBBL,30HCMPBL.39HJAL1MOVDL.，=/MOVAH,02HINT21HMOVDL.BL;SUBDL,SOHMOVAH,02HINT21HJMPL2L1：MOVDL,'='MOVAH,02HINT21HADCBL,06HAAASUBBL,30HMOVBH,BLANDBH,0FOHMOVCL,4RORBH.CLMOVDUBHADDDL,30HMOVAH.O2HINT21HANDBL.OFHMOVDL.BL-ADDDL.30HMOVAH,02HINT21HL2：MOVAH.4GHINT21HCODESENDSENDSTART評(píng)語：.實(shí)驗(yàn)?zāi)康募皟?nèi)容.實(shí)驗(yàn)?zāi)康膶W(xué)習(xí)程序設(shè)計(jì)的基本方法和技能，掌握匯編語言設(shè)計(jì)、編寫、調(diào)試和運(yùn)營程序的方法。.實(shí)驗(yàn)內(nèi)容（-）編寫程序1、選做下列題目：。1）編寫程序完畢：從無符號(hào)數(shù)X、Y、Z選取最小數(shù)存放在W單元中。指出W.單元的地址及其內(nèi)容。o2）從鍵盤輸入兩個(gè)一位的十進(jìn)制數(shù),求其和，存入RESULT單元并從屏幕上輸出。j2、寫出DEBUG命令的含義,g、q、t、f、p、d、a,（二）寫出上機(jī)過程,（三）純熟使用DEBUG高度程序觀測(cè)運(yùn)營結(jié)果.實(shí)驗(yàn)環(huán)境pc機(jī)、MasmforWindows2023..實(shí)驗(yàn)方法實(shí)驗(yàn)i.1采用單分支結(jié)構(gòu)程序設(shè)計(jì)；實(shí)驗(yàn)1.2采用順序結(jié)構(gòu)，用非壓縮BCD碼加法調(diào)整指令A(yù)AA實(shí)現(xiàn)對(duì)兩數(shù)之和的調(diào)整，使輸出對(duì)的。.實(shí)驗(yàn)環(huán)節(jié)實(shí)驗(yàn)1.1：一、輸入三個(gè)數(shù)X、Y、Z,分別存入三個(gè)內(nèi)存空間；二、把X的值付給寄存器BL,再兩兩比較，把最小的數(shù)賦值給BL;二、顯示BLo實(shí)驗(yàn)1.2:一、輸入兩個(gè)數(shù)分別存入兩個(gè)寄存器中；二、兩數(shù)求和，AAA調(diào)整；三、保存并顯示。.實(shí)驗(yàn)結(jié)論實(shí)驗(yàn)1.1：實(shí)驗(yàn)數(shù)據(jù)不高于159.圈DOSBox0.74,Cpuspeed:3001111ZZ10064地址如下:64Programterminatednormally-d00770:0000G8036431310DQ?GO-GO00G803?A32320D..dllzZZ0770:00100000OO08036430-30OD000000000002dOOTOC\o"1-5"\h\z0770：00Z0B870078ED8BA7007-8EDABA00008D36GO.p....p60770:0030GOB40ACD21B2ODB4-QZCD21BZOAB402CD....0770:005076OF8A5COZ80EB30-0ZC3B3OAF6E346EZv.A...0F0770:0060Fl8A5C0280EB3002-C38AOEIFGOZBFl88。+.0770:0070440283c60A8BD6FE-0EIEOQ803EIEOOOOD>..-Aa實(shí)驗(yàn)1.2:圖DOSBox0.74,Cpuspeed:3000cycles.Frameskip?3+3=12Pressanykeytocontinue.實(shí)驗(yàn)分析實(shí)驗(yàn)1.1：數(shù)據(jù)不能大于159;最小值的顯示十六進(jìn)制。實(shí)驗(yàn)1.2：對(duì)于兩數(shù)相加也許產(chǎn)生進(jìn)位的情況可以通過AAA調(diào)整;十六進(jìn)制轉(zhuǎn)十進(jìn)制可以通過除法求余之法。附件.程序流程圖實(shí)驗(yàn)1.1:實(shí)驗(yàn)1.2:結(jié)束.匯編語言源程序?qū)嶒?yàn)1.1:DATASSEGMENT；此處輸人敢據(jù)破代*WDB8LENDB?XDB8dup(?)：ORG100HW1DBSLEN1DB?YDB8DUP(?)W2DB8LEN2DB?ZDB8DUP(?)EDB3FDB?DATASENDSSTACKSSEGMENTSTACKSENDSCODESSEGMENTASSUMEC5:CODE5.DS：DATAS.S5：5TACKSSTART：MOVAX,DATASMOVDS,AX；此處物人代嗚傲.代盛MOVDX.5EGWMOVDS,DXMOVDX.OFFSETWLEASI.WP2：MOVAH,OAHINT21HMOVDL.13MOVAH,02HINT21HMOVDL,10MOVAH.02HINT21HXORAL,ALmovcl,[SI+l]xorch,chdeccxMOVF.CLCMPCX,0；當(dāng)輸人的聶一色敢M不用乘10JBEP3P1：movBL.[5I+2]SUBBL,30HADDAL,BLmovBI.10muIBlINGSIloopp1P3：MOVBL.[SI+2]SUBBL,30HADDAL.BLMOVCL,FSUBSI,OX。MOV[SI+2]AL;ADDDX,10ADDSI,10MOVDX.SI；CMPE.3；JAP4：JBP