試卷第=page11頁，共=sectionpages33頁試卷第=page1212頁，共=sectionpages11頁第23課同角三角函數(shù)的基本關(guān)系與誘導公式學校:___________姓名：___________班級：___________考號：___________【基礎(chǔ)鞏固】1．（2022·全國·高三專題練習）下列各數(shù)中，與SKIPIF1<0相等的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】C【解析】SKIPIF1<0.故選：C2．（2022·福建·三明一中模擬預測）已知SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】B【解析】SKIPIF1<0.故選：B.3．（2022·江蘇·南京市天印高級中學模擬預測）若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0【答案】C【解析】SKIPIF1<0,解得SKIPIF1<0故選：C4．（2022·遼寧葫蘆島·二模）若SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．-3 D．3【答案】C【解析】SKIPIF1<0，分子分母同除以SKIPIF1<0，SKIPIF1<0，解得：SKIPIF1<0故選：C5．（2022·湖北·襄陽五中模擬預測）已知函數(shù)SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0的值為（）A．-1 B．1 C．3 D．-3【答案】D【解析】SKIPIF1<0，所以SKIPIF1<0.SKIPIF1<0.故選：D6．（2022·全國·高三專題練習）已知SKIPIF1<0，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【解析】因為SKIPIF1<0，則SKIPIF1<0，原式SKIPIF1<0SKIPIF1<0.故選：A.7．（2022·全國·高三專題練習）已知SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0等于（

）A．1 B．SKIPIF1<0 C．SKIPIF1<0 D．2或6【答案】C【解析】因為SKIPIF1<0，則SKIPIF1<0，解得SKIPIF1<0，又SKIPIF1<0，所以SKIPIF1<0.故選：C.8．（2022·廣東茂名·二模）已知SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0的值為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】C【解析】解：因為SKIPIF1<0，所以SKIPIF1<0．所以SKIPIF1<0，所以SKIPIF1<0，得SKIPIF1<0，因為SKIPIF1<0，所以SKIPIF1<0SKIPIF1<0．故選：C．9．（多選）（2022·全國·高三專題練習）已知SKIPIF1<0，則下列結(jié)論正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】ACD【解析】對于A選項，SKIPIF1<0，故A選項正確；對于B選項，SKIPIF1<0，故B選項錯誤；對于C選項，SKIPIF1<0，故C選項正確；對于D選項，SKIPIF1<0，故D選項正確.故選：ACD10．（2022·福建莆田·模擬預測）若SKIPIF1<0，則SKIPIF1<0______．【答案】SKIPIF1<0【解析】∵SKIPIF1<0，∴SKIPIF1<0．故答案為：SKIPIF1<0.11．（2022·湖南益陽·高三階段練習）已知SKIPIF1<0，則SKIPIF1<0__________.【答案】SKIPIF1<0【解析】SKIPIF1<0SKIPIF1<0，故答案為：SKIPIF1<012．（2022·山東·肥城市教學研究中心模擬預測）若SKIPIF1<0，且SKIPIF1<0，則SKIPIF1<0_______．【答案】SKIPIF1<0【解析】由SKIPIF1<0得SKIPIF1<0，故SKIPIF1<0，所以SKIPIF1<0SKIPIF1<0，解得SKIPIF1<0，或SKIPIF1<0.因為SKIPIF1<0，所以SKIPIF1<0，所以SKIPIF1<0SKIPIF1<0SKIPIF1<0.故答案為：SKIPIF1<013．（2022·廣東潮州·二模）已知SKIPIF1<0，SKIPIF1<0，則SKIPIF1<0______．【答案】SKIPIF1<0【解析】SKIPIF1<0，得SKIPIF1<0，SKIPIF1<0，因為SKIPIF1<0，所以SKIPIF1<0，故SKIPIF1<0．故答案為：SKIPIF1<014．（2022·全國·高三專題練習）化簡：SKIPIF1<0________.【答案】SKIPIF1<0【解析】原式SKIPIF1<0.故答案為：SKIPIF1<0.15．（2022·江蘇南通·模擬預測）若SKIPIF1<0＝3，則SKIPIF1<0＝________．【答案】SKIPIF1<0【解析】SKIPIF1<0SKIPIF1<0故答案為：SKIPIF1<0.16．（2022·北京·中關(guān)村中學高三開學考試）已知SKIPIF1<0，則SKIPIF1<0____________，若角SKIPIF1<0與角SKIPIF1<0關(guān)于SKIPIF1<0軸對稱，則SKIPIF1<0____________．【答案】

SKIPIF1<0

SKIPIF1<0【解析】因為SKIPIF1<0，所以SKIPIF1<0；若角SKIPIF1<0與角SKIPIF1<0關(guān)于SKIPIF1<0軸對稱，則SKIPIF1<0.故答案為：SKIPIF1<0，SKIPIF1<0.17．（2022·全國·高三專題練習）已知SKIPIF1<0．（1）求SKIPIF1<0的值；

（2）求SKIPIF1<0的值．【解】（1）因為SKIPIF1<0，所以SKIPIF1<0，則SKIPIF1<0.（2）聯(lián)立SKIPIF1<0，解得SKIPIF1<0，則SKIPIF1<0.18．（2022·浙江·高三專題練習）已知SKIPIF1<0是關(guān)于SKIPIF1<0的方程SKIPIF1<0的兩個實根，且SKIPIF1<0.（1）求SKIPIF1<0的值；（2）求SKIPIF1<0的值.【解】解：SKIPIF1<0，SKIPIF1<0是關(guān)于SKIPIF1<0的方程SKIPIF1<0的兩個實根，SKIPIF1<0，解得：SKIPIF1<0，又SKIPIF1<0，SKIPIF1<0，SKIPIF1<0，解得：SKIPIF1<0（1）SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0（2）SKIPIF1<019．（2022·全國·高三專題練習）已知角SKIPIF1<0的終邊經(jīng)過點SKIPIF1<0(SKIPIF1<0).（1）求SKIPIF1<0的值；（2）若SKIPIF1<0是第二象限角，求SKIPIF1<0的值.【解】解：（1）SKIPIF1<0,SKIPIF1<0,即SKIPIF1<0SKIPIF1<0SKIPIF1<0.又SKIPIF1<0角SKIPIF1<0的終邊經(jīng)過點SKIPIF1<0(SKIPIF1<0)，SKIPIF1<0，故SKIPIF1<0；（2）SKIPIF1<0是第二象限角，SKIPIF1<0，則SKIPIF1<0，SKIPIF1<0，SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0.【素養(yǎng)提升】1．（2022·全國·模擬預測）已知角SKIPIF1<0的頂點與原點重合，始邊與SKIPIF1<0軸的非負半軸重合，SKIPIF1<0為角SKIPIF1<0終邊上的一點，將角SKIPIF1<0終邊逆時針旋轉(zhuǎn)SKIPIF1<0得到角SKIPIF1<0的終邊，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】A【解析】由題可知SKIPIF1<0，所以SKIPIF1<0，則SKIPIF1<0SKIPIF1<0.故選：A．2．（2022·全國·高三專題練習）函數(shù)SKIPIF1<0的值域為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0【答案】D【解析】解：SKIPIF1<0SKIPIF1<0則SKIPIF1<0且SKIPIF1<0，令SKIPIF1<0，則SKIPIF1<0，則SKIPIF1<0，SKIPIF1<0，當SKIPIF1<0時，SKIPIF1<0，當SKIPIF1<0時，SKIPIF1<0，故SKIPIF1<0的值域為SKIPIF1<0.故選：D.3．（多選）（2022·江蘇·高三專題練習）已知角SKIPIF1<0滿足SKIPIF1<0，則表達式SKIPIF1<0的取值可能為（

）A．-2 B．-1或1 C．2 D．-2或2或0【答案】AC【解析】當SKIPIF1<0為奇數(shù)時，原式SKIPIF1<0；當SKIPIF1<0為偶數(shù)時，原式SKIPIF1<0.∴原表達式的取值可能為SKIPIF1<0或2.

故選：AC4．（2022·遼寧實驗中學模擬預測）已知SKIPIF1<0，則SKIPIF1<0_________．【答案】SKIPIF1<0【解析】SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0．故答案為：SKIPIF1<0．5．（2022·全國·高三專題練習）已知角SKIPIF1<0，若角SKIPIF1<0與角SKIPIF1<0的終邊相同，則SKIPIF1<0的值為______.【答案】SKIPIF1<0【解析】SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0SKIPIF1<0.故答案為：SKIPIF1<06．（2022·四川省瀘縣第一中學三模（理））已知SKIPIF1<0，則SKIPIF1<0的最大值為____________【答案】SKIPIF1<0【解析】SKIPIF1<0，SKIPIF1<0SKIPIF1<0，SKIPIF1<0，即SKIPIF1<0