A.2iB.-2iC.2D.-2D.或EQ\*jc3\*hps21\o\al(\s\up9(—→),B)EQ\*jc3\*hps21\o\al(\s\up9(—→),B)EQ\*jc3\*hps21\o\al(\s\up9(—→),D)A.3B.-3C.-2D.25.將函數(shù)f(x(=sin(2x+φ((0<φ<π)的圖象上所有點(diǎn)向右平移個(gè)單位后得到的圖象A.D.高一強(qiáng)基班數(shù)學(xué)第1頁共4頁6.函數(shù)f(x(=Asin(ωx+φ((A>0()A.0B.1C.2D.3EQ\*jc3\*hps14\o\al(\s\up9(八),AB)EQ\*jc3\*hps21\o\al(\s\up9(—→),C)EQ\*jc3\*hps21\o\al(\s\up9(—→),A)EQ\*jc3\*hps21\o\al(\s\up9(—→),B)A.B.3A.11B.9C.79.已知函數(shù)f(x(=cos(2x-，下列選項(xiàng)正確的有()A.f(x(的最小正周期為πB.函數(shù)f(x(的單調(diào)遞增區(qū)間為C.f(x(在區(qū)間(0,上只有一個(gè)零點(diǎn)D.函數(shù)f(x(在區(qū)間,的值域?yàn)?1,EQ\*jc3\*hps21\o\al(\s\up7(→),b)EQ\*jc3\*hps21\o\al(\s\up7(→),b)EQ\*jc3\*hps21\o\al(\s\up7(→),b)EQ\*jc3\*hps21\o\al(\s\up8(→),b)EQ\*jc3\*hps21\o\al(\s\up8(→),b)11.△ABC內(nèi)角A,B,C的對(duì)邊分別為a,b,c．已知bsinA=(3b-c(sinB，且cosA=，則下列結(jié)論正確的是()A.a+c=3bB.tanA=22C.△ABC的周長為4cD.△ABC的面積為a2已知向量=(-1,0(，EQ\*jc3\*hps21\o\al(\s\up8(→),b)=(m,1(，且與EQ\*jc3\*hps21\o\al(\s\up8(→),b)的夾角為．EQ\*jc3\*hps21\o\al(\s\up8(→),b)EQ\*jc3\*hps21\o\al(\s\up7(→),b)EQ\*jc3\*hps21\o\al(\s\up7(→),b)高一強(qiáng)基班數(shù)學(xué)第3頁共4頁若都有|f(x1(-f(x2(|≤m恒成立，求實(shí)數(shù)m的取值范圍．c(2sinC-sinB(．(1(求A；(2(若a=3，求三角形ABC周長的最大值.(1)求函數(shù)f(x)解析式及最小正周期；(2)若函數(shù)f(x)在[-a,a]上不單調(diào)，求a的取值范圍；1--8：ADDDBDBB9.ACD10.AD11.ABD(1)因?yàn)橄蛄?(-1,0(，EQ\*jc3\*hps21\o\al(\s\up8(→),b)=(m,1(，且與EQ\*jc3\*hps21\o\al(\s\up8(→),b)的夾角為，所以，EQ\*jc3\*hps21\o\al(\s\up8(→),b)=(-1,1(，則+2EQ\*jc3\*hps21\o\al(\s\up8(→),b)=(-1,0(+2(-1,1(=(-3,2(，(2)由(1)可得+λEQ\*jc3\*hps21\o\al(\s\up7(→),b)=(-1,0(+λ(-1,1(=(-λ-1,λ(，且+2EQ\*jc3\*hps21\o\al(\s\up7(→),b)=(-3,2(，EQ\*jc3\*hps21\o\al(\s\up7(→),b)EQ\*jc3\*hps21\o\al(\s\up7(→),b)EQ\*jc3\*hps21\o\al(\s\up8(→),b)EQ\*jc3\*hps21\o\al(\s\up8(→),b)EQ\*jc3\*hps21\o\al(\s\up7(→),b)EQ\*jc3\*hps21\o\al(\s\up7(→),b)(1)由x2-x-2=0，得x=-1或x=2，“tanα是方程x2-x-2=0的一個(gè)實(shí)根，且α是第三象限角，高一強(qiáng)基班數(shù)學(xué)答案第1頁共4頁:(sinα-cosα)2=1-2sinαcosα=，分(1)由=(1,1(,EQ\*jc3\*hps21\o\al(\s\up7(→),b)=(sinx,cosx(，再由Yx1EQ\*jc3\*hps18\o\al(\s\up3(Γ),L)f(x1(-f(x2(|≤m恒成立，則有|f(x(max-f(x(min|≤m，即m≥,故實(shí)數(shù)m的取值范圍m≥(1)“2asinA=(2b-c(sinB+c(2sinC-sinB(，:2a2=(2b-c(b+(2c-b(c，2-bc，“A∈(0,π(2-3≤32(3)根據(jù)題意可得AEQ\*jc3\*hps21\o\al(\s\up9(—→),D)=AEQ\*jc3\*hps21\o\al(\s\up9(—→),B)+BEQ\*jc3\*hps21\o\al(\s\up9(—→),D)=AEQ\*jc3\*hps21\o\al(\s\up9(—→),B)+BEQ\*jc3\*hps21\o\al(\s\up9(—→),C)=AEQ\*jc3\*hps21\o\al(\s\up9(—→),B)+AEQ\*jc3\*hps21\o\al(\s\up9(—→),C)，(1)函數(shù)f(x)=3sin(π+x)cos(π-x)-sin2+x(+=3sinxcosx-cos2x+可得函數(shù)f(x)在區(qū)間-+kπ,