1、數(shù)值逼近實(shí)習(xí)題 目 二重積分的復(fù)化梯形公式 專 業(yè) 信息與計(jì)算科學(xué) 班 級(jí) 計(jì)算092 學(xué) 號(hào) 3090811072 學(xué) 生 指導(dǎo)教師 2011 年一、實(shí)驗(yàn)?zāi)康?.利用Gauss-Legendre公式計(jì)算積分2.比較計(jì)算誤差與實(shí)際誤差二、數(shù)學(xué)模型 三、算法Step 1:輸入等分?jǐn)?shù)nStep2:輸入積分上下限；Step3: 求出步長及對(duì)應(yīng)個(gè)點(diǎn);Step4: 由計(jì)算積分結(jié)果Step5:將積分結(jié)果輸出；四、程序#includeusing namespace std;#includemath.h#define N 10double f(double x)double z; z=cos(x); retu

2、rn(z);int main() int i, n,m;double XN,AN,F=0;cout請(qǐng)輸入代數(shù)精度nn; m=(n+1)/2;switch(m) case 1:X1=0;A1=2; break;case 2:X1=0.5773502692;X2=-X1;A1=A2=1;break; case 3:X1=0.77459666920;X2=-X1;X3=0;A1=A2=0.5555555556;A3=0.8888888889;break;case 4:X1=0.8611363116;X2=-X1;X3=0.3399810436;X4=-X3;A1=A2=0.3478548451; A

3、3=A4=0.6521451549; break;case 5:X1=0.9061798459;X2=-X1;X3=0.53846931010;X4=-X3;X5=0;A1=A2=0.2369268851; A3=A4=0.4786286705;A5=0.5688888889; break;case 6:X1=0.9324695142;X2=-X1;X3=0.6612093865;X4=-X3;X5=0.12386191816;X6=-X5; A1=A2=0.1713244924;A3=A4=0.3607615730;A5=A6=0.4679139346; break; case 7:X1=0

4、.9491079123;X2=-X1;X3=0.7415311856;X4=-X3;X5=0.40584515140;X6=-X5;X7=0; A1=A2=0.1294849662;A3=A4=0.2797053915;A5=A6=0.3818300505;A7=0.4179591834; break;case 8:X1=0.9602898565;X2=-X1;X3=0.7966664774;X4=-X3;X5=0.5255324099;X6=-X5;X7=0.1834346425; X8=-X7;A1=A2=0.1012285363;A3=A4=0.2223810345;A5=A6=0.3137066459;A7=A8=0.3626837834; break; default:printf(errorn);for(i=1;i=m;i+)F=F+f(Xi)*Ai;cout具有n次精度的高斯勒讓德積分F(x)=Fendl;return 0;五、數(shù)