1.基本參數,,單位,,,,單位,

混凝土強度等級,25,,,彎矩M=,18.8,kN.m,

扭矩T=,7.3,kN.m,,V=,16,kN,

Astl=,804,mm2,,Ast1=,50.3,mm2,

保護層厚度c=,25,mm,,as=,35,mm,

ft=,1.27,N/mm2,,fc=,11.9,N/mm2,

fyv=,300,N/mm2,,fy=,300,N/mm2,

b=,250,mm,,h=,400,mm,

bcor=,200,mm,,hcor=,350,mm,

Acor=,70000,mm2,,Ucor=,1100,mm,

Wt=b2/6*(3h-b),9895833.333,mm3,,,,,

ρtl=Astl/b/h=,0.804,,,,,,

,,,,,,,,

2.驗算截面尺寸,,,,,,,

hw=h0=,365,mm,,hw/b=,1.46,<,4

V/bh0+T/0.8Wt=,1.097447729,N/mm2,<,0.25βcfc=,2.975,N/mm2,截面符合要求

3.驗算是否可不考慮剪力,,,,,,,

0.35ftbh0=,40.560625,kN,>,V=,16,kN,可忽略剪力

4.驗算是否可不考慮扭矩,,,,,,,

0.175ftWt=,2.199348958,kN.m,<,扭矩T=,7.3,kN.m,不能忽略扭矩

5.驗算是否按計算配置抗剪、抗扭鋼筋,,,,,,,

V/bh0+T/Wt=,,N/mm2,>,0.7ft=,0.889,N/mm2,應按計算配置抗剪、抗扭鋼筋

6.計算剪扭構件混凝土承載力降低系數βt,,,,,,,

βt=1.5/(1+0.5VWt/Tbh0=,1.340666406,,>,,1,取βt=,1

7.計算箍筋用量,,,,,,,

1）計算抗扭箍筋用量,,,,,,,

取ζ=,1,,,,,,

Ast1/s=(T-0.35ftWt)/(1.2*ζ^0.5*fyv*Acor)=,0.115,,,s=,436.5936816,,

2）計算抗剪箍筋用量,,,,,,,

Asv1/s=(V-0.7(1.5-βt)ftbh0)/(1.25fyvh0)=,-0.090,,,,,,

3）抗剪和抗扭箍筋用量,,,,,,,

Asv1'/s=Asv1/s+Ast1/s=,0.296,,,,,,

選用箍筋直徑φ=,8,mm,,單支箍筋面積Asv1'=,50.3,,

箍筋間距s=,169.6248002,mm,,取s=,160,,

4）驗算配箍率,,,,,,,

"ρsv,min=0.28*ft/fyv=",0.118533333,,<,配箍率ρsv=Asv/bs=,0.251327412,,滿足要求

8.計算抗扭縱筋用量,,,,,,,

1）求Astl,,,,,,,

Astl=ζ*fyv*Ast1*ucor/fy/s=,343.1,,抗扭縱筋根數,2,,,

選=,2,φ,16,,,,

As=,402.1238597,>,343.1,滿足要求,,,

2）驗算配筋率,,,,,,,

受扭縱向鋼筋的配筋率ρtl=Astl/bh=,0.40212386,,,,,,

T/Vb=,1.825,T=,1.825,,