專題14函數(shù)的圖象(二)考點一函數(shù)圖象的變換一、單選題1．為了得到函數(shù)SKIPIF1<0的圖象，只需把函數(shù)SKIPIF1<0的圖象上的所有點（

）A．向左平移2個單位長度，再向上平移2個單位長度B．向右平移2個單位長度，再向下平移2個單位長度C．向左平移1個單位長度，再向上平移1個單位長度D．向右平移1個單位長度，再向上平移1個單位長度2．要得到函數(shù)SKIPIF1<0的圖象，只需將指數(shù)函數(shù)SKIPIF1<0的圖象（

）A．向左平移1個單位 B．向右平移1個單位C．向左平移SKIPIF1<0個單位 D．向右平移SKIPIF1<0個單位3．為了得到SKIPIF1<0的圖象，只需將SKIPIF1<0的圖象（

）A．向右平移1個單位，再向下平移2個單位B．向右平移1個單位，再向上平移2個單位C．向左平移1個單位，再向上平移2個單位D．向左平移1個單位，再向下平移2個單位4．為了得到函數(shù)SKIPIF1<0的圖像，只需將函數(shù)SKIPIF1<0的圖像（

）A．向右平移3個單位，再向上平移2個單位B．向左平移3個單位，再向下平移2個單位C．向右平移3個單位，再向下平移2個單位D．向左平移3個單位，再向上平移2個單位5．要得到SKIPIF1<0的圖像，只要將SKIPIF1<0的圖像（

）A．向左平移SKIPIF1<0個單位 B．向右平移SKIPIF1<0個單位C．向左平移SKIPIF1<0個單位 D．向右平移SKIPIF1<0個單位6．把函數(shù)SKIPIF1<0圖象上所有點的橫坐標都伸長為原來的2倍,縱坐標不變,再把圖象向右平移2個單位長度,此時圖象對應(yīng)的函數(shù)為SKIPIF1<0,則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．0 D．SKIPIF1<07．已知函數(shù)SKIPIF1<0的圖象如下圖所示，則SKIPIF1<0的大致圖象是（

）A． B．C． D．8．若函數(shù)SKIPIF1<0的圖象向左平移一個單位長度，所的圖象與曲線SKIPIF1<0關(guān)于SKIPIF1<0軸對稱，則SKIPIF1<0（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0二、解答題9．利用函數(shù)SKIPIF1<0的圖象，作出下列各函數(shù)的圖象．(1)SKIPIF1<0；(2)SKIPIF1<0(3)SKIPIF1<0；(4)SKIPIF1<0；(5)SKIPIF1<0；(6)SKIPIF1<0．10．已知函數(shù)SKIPIF1<0定義在SKIPIF1<0上的圖象如圖所示，請分別畫出下列函數(shù)的圖象：

(1)SKIPIF1<0；(2)SKIPIF1<0；(3)SKIPIF1<0；(4)SKIPIF1<0；(5)SKIPIF1<0；(6)SKIPIF1<0.考點二利用函數(shù)圖象解決不等式問題一、單選題1．如圖為函數(shù)SKIPIF1<0和SKIPIF1<0的圖象，則不等式SKIPIF1<0的解集為（）

A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<02．將SKIPIF1<0的圖象向右平移2個單位長度后得到函數(shù)SKIPIF1<0的圖象，則不等式SKIPIF1<0的解集是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<03．已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的奇函數(shù)，當(dāng)SKIPIF1<0時，SKIPIF1<0，則不等式SKIPIF1<0的解集是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<04．已知函數(shù)SKIPIF1<0，SKIPIF1<0，則不等式SKIPIF1<0的解集為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<05．已知函數(shù)SKIPIF1<0的定義域為R，SKIPIF1<0，且SKIPIF1<0在SKIPIF1<0上遞增，則SKIPIF1<0的解集為（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<06．已知函數(shù)SKIPIF1<0，則SKIPIF1<0的解集是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0二、多選題7．設(shè)函數(shù)SKIPIF1<0的定義域為R，滿足SKIPIF1<0，且當(dāng)SKIPIF1<0時，SKIPIF1<0，若對任意SKIPIF1<0，都有SKIPIF1<0，則實數(shù)m的取值可以是（

）A．3 B．4 C．SKIPIF1<0 D．SKIPIF1<08．已知函數(shù)SKIPIF1<0是定義在SKIPIF1<0上的偶函數(shù)，當(dāng)SKIPIF1<0時，SKIPIF1<0的圖象如圖所示，則滿足不等式SKIPIF1<0的x可能是（

）A．SKIPIF1<0 B．0 C．1 D．29．定義在R上的函數(shù)SKIPIF1<0，滿足SKIPIF1<0，且當(dāng)SKIPIF1<0時，SKIPIF1<0，則使得SKIPIF1<0在SKIPIF1<0上恒成立的m可以是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<010．函數(shù)SKIPIF1<0，SKIPIF1<0，其中SKIPIF1<0.記SKIPIF1<0，設(shè)SKIPIF1<0，若不等式SKIPIF1<0恒有解，則實數(shù)SKIPIF1<0的值可以是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<0三、填空題11．已知函數(shù)SKIPIF1<0，則不等式SKIPIF1<0的解集是______.12．不等式SKIPIF1<0的解集為________．13．定義在R上的函數(shù)SKIPIF1<0滿足SKIPIF1<0，且當(dāng)SKIPIF1<0時，SKIPIF1<0．若對任意SKIPIF1<0，都有SKIPIF1<0，則t的取值范圍是__________．14．已知函數(shù)SKIPIF1<0，若不等式SKIPIF1<0恒成立，則實數(shù)a的范圍是____________．四、解答題15．已知函數(shù)SKIPIF1<0，SKIPIF1<0．(1)在給出的坐標系中畫出函數(shù)SKIPIF1<0的圖像；(2)若關(guān)于SKIPIF1<0的不等式SKIPIF1<0恒成立，求實數(shù)SKIPIF1<0的取值范圍．16．已知函數(shù)SKIPIF1<0.(1)在坐標系中作出函數(shù)SKIPIF1<0的圖象；(2)若SKIPIF1<0，求實數(shù)SKIPIF1<0的取值范圍.考點三利用函數(shù)圖象解決方程的根與交點問題一、單選題1．方程SKIPIF1<0的解的個數(shù)是（

）.A．0個 B．1個 C．2個 D．3個2．已知函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0有兩個不同的零點，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<03．已知函數(shù)SKIPIF1<0，若方程SKIPIF1<0有四個不同的解SKIPIF1<0且SKIPIF1<0，則SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<04．函數(shù)SKIPIF1<0的圖象和函數(shù)SKIPIF1<0的圖象的交點的個數(shù)為（

）A．1 B．2 C．3 D．45．已知函數(shù)SKIPIF1<0，若實數(shù)SKIPIF1<0，則函數(shù)SKIPIF1<0的零點個數(shù)為（

）A．0或1 B．1或2 C．1或3 D．2或36．已知函數(shù)SKIPIF1<0，若關(guān)于SKIPIF1<0的方程SKIPIF1<0恰有5個不同的實根，則SKIPIF1<0的取值范圍為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<07．已知函數(shù)SKIPIF1<0，若方程SKIPIF1<0有四個不同的實數(shù)根，則實數(shù)a的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<08．已知函數(shù)SKIPIF1<0，若方程SKIPIF1<0有兩個實根，且兩實根之和小于0，則實數(shù)SKIPIF1<0的取值范圍是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<09．函數(shù)SKIPIF1<0的圖像與函數(shù)SKIPIF1<0的圖像所有交點的橫坐標之和等于（

）A．8 B．10 C．12 D．1410．已知函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0有6個不同的零點，且最小的零點為SKIPIF1<0，則SKIPIF1<0（

）A．6 B．SKIPIF1<0 C．2 D．SKIPIF1<0二、多選題11．關(guān)于x的方程SKIPIF1<0，給出下列四個判斷：其中正確的為（

）A．存在實數(shù)k，使得方程恰有4個不同的實根；B．存在實數(shù)k，使得方程恰有5個不同的實根；C．存在實數(shù)k，使得方程恰有6個不同的實根；D．存在實數(shù)k，使得方程恰有8個不同的實根；12．已知函數(shù)SKIPIF1<0，若方程SKIPIF1<0有四個不等實根SKIPIF1<0（SKIPIF1<0），則下列說法正確的是（

）A．SKIPIF1<0 B．SKIPIF1<0C．SKIPIF1<0 D．SKIPIF1<0最小值為213．已知函數(shù)SKIPIF1<0，若關(guān)于SKIPIF1<0的方程SKIPIF1<0有兩解，則實數(shù)SKIPIF1<0的值可能為（

）A．SKIPIF1<0 B．SKIPIF1<0 C．SKIPIF1<0 D．SKIPIF1<014．已知函數(shù)SKIPIF1<0，若函數(shù)SKIPIF1<0恰好有4個不同的零點，則實數(shù)SKIPIF1<0的取值可以是（

）A．SKIPIF1<0 B．SKIPIF1<0 C．0 D．2三、填空題15．已知定義在SKIPIF1<0上的函數(shù)SKIPIF1<0，滿足SKIPIF1<0，當(dāng)SKIPIF1<0時，SKIPIF1<0，若方程SKIPIF1<0在區(qū)間SKIPIF1<0內(nèi)有實數(shù)解，則實數(shù)SKIPIF1<0的取值范圍為__________.16．已知SKIPIF1<0，若關(guān)于SKIPIF1