七年級分式運算試卷及答案一、選擇題（每題3分，共30分）1.計算下列分式的值：A.\(\frac{1}{2}\)B.\(\frac{3}{4}\)C.\(\frac{2}{3}\)D.\(\frac{5}{6}\)答案：A2.兩個分式相加，如果分母相同，那么：A.直接相加B.先通分后相加C.先約分后相加D.無法相加答案：A3.分式\(\frac{a}\)與\(\frac{c}fjzbbvn\)相乘，正確的運算是：A.\(\frac{a\timesc}{b\timesd}\)B.\(\frac{a\divc}{b\divd}\)C.\(\frac{a+c}{b+d}\)D.\(\frac{a-c}{b-d}\)答案：A4.分式\(\frac{a}\)除以\(\frac{c}lzrlhth\)的正確運算是：A.\(\frac{a}\times\frac{c}p3tvvbz\)B.\(\frac{a}\div\frac{c}9ltlxbj\)C.\(\frac{a}\times\frac3nfdplz{c}\)D.\(\frac{a}\div\fracr7v9p9v{c}\)答案：C5.如果\(\frac{a}=\frac{c}pp199dl\)，那么\(ad=bc\)是：A.正確B.錯誤C.有時正確有時錯誤D.無法確定答案：A6.以下哪個選項不是分式的基本性質(zhì)？A.分式的分子和分母同時乘以或除以同一個非零數(shù)，分式的值不變。B.分式的分子和分母同時加上或減去同一個數(shù)，分式的值不變。C.分式的分子和分母同時乘以或除以同一個數(shù)，分式的值不變。D.分式的分子和分母同時乘以或除以同一個非零數(shù)，分式的值不變。答案：B7.計算\(\frac{1}{2}+\frac{1}{3}\)的結(jié)果是：A.\(\frac{5}{6}\)B.\(\frac{3}{5}\)C.\(\frac{5}{3}\)D.\(\frac{3}{6}\)答案：A8.計算\(\frac{2}{3}\times\frac{3}{4}\)的結(jié)果是：A.\(\frac{6}{12}\)B.\(\frac{1}{2}\)C.\(\frac{6}{4}\)D.\(\frac{3}{2}\)答案：B9.計算\(\frac{4}{5}\div\frac{2}{5}\)的結(jié)果是：A.\(\frac{2}{5}\)B.\(\frac{4}{2}\)C.\(\frac{4}{5}\times\frac{5}{2}\)D.\(\frac{2}{1}\)答案：C10.化簡\(\frac{2x}{3x}\)的結(jié)果是：A.\(\frac{2}{3}\)B.\(\frac{x}{3}\)C.\(\frac{2x}{3}\)D.\(\frac{3}{2}\)答案：A二、填空題（每題4分，共20分）11.計算\(\frac{3}{4}-\frac{1}{2}\)的結(jié)果是______。答案：\(\frac{1}{4}\)12.計算\(\frac{5}{6}\times\frac{3}{5}\)的結(jié)果是______。答案：\(\frac{1}{2}\)13.計算\(\frac{2}{3}\div\frac{4}{3}\)的結(jié)果是______。答案：\(\frac{1}{2}\)14.化簡\(\frac{6x^2}{9x}\)的結(jié)果是______。答案：\(\frac{2x}{3}\)15.如果\(\frac{a}=2\)，那么\(b=\frac{a}{2}\)是______。答案：正確三、解答題（每題10分，共50分）16.計算下列分式的混合運算：\[\frac{1}{2}+\frac{3}{4}-\frac{1}{3}+\frac{5}{6}\]答案：\[\frac{1}{2}+\frac{3}{4}-\frac{1}{3}+\frac{5}{6}=\frac{3}{6}+\frac{9}{12}-\frac{4}{12}+\frac{10}{12}=\frac{18}{12}=\frac{3}{2}\]17.計算下列分式的乘除混合運算：\[\frac{2}{3}\times\frac{4}{5}\div\frac{8}{15}\]答案：\[\frac{2}{3}\times\frac{4}{5}\div\frac{8}{15}=\frac{2}{3}\times\frac{4}{5}\times\frac{15}{8}=\frac{2\times4\times15}{3\times5\times8}=\frac{120}{120}=1\]18.已知\(\frac{a}=\frac{c}xd1rhbh\)，求\(\frac{a+c}{b+d}\)的值。答案：\[\frac{a+c}{b+d}=\frac{a}=\frac{c}pjpb99d\]19.化簡下列分式：\[\frac{3x^2-6x}{2x^2-4x}\]答案：\[\frac{3x^2-6x}{2x^2-4x}=\frac{3x(x-2)}{2x(x-2)}=\frac{3}{2}\]20.解下列分式方程：\[\frac{1}{x-2}+\frac{1}{x+2}=\frac{4}{x^2-4}\]答案：\[\frac{1}{x-2}+\frac{1}{x+2}=\frac{4}{x^2-4}\]\[\frac{(x+2)+(x-2