2025年GRE數(shù)學(xué)算術(shù)真題模擬卷考試時(shí)間：______分鐘總分：______分姓名：______Section1:QuantitativeReasoning*Directions:Foreachquestion,indicatethebestanswer,usingthedirectionsgivenforthetypeofquestion.Fillintheappropriatecircleontheanswersheet.1.If3timesanumberis18,whatis5timesthenumber?A.20B.25C.30D.35E.402.Whichofthefollowingisequivalenttotheexpression(y+4)-(y-7)?A.11B.2y-3C.2y+11D.11-2yE.4y-113.Ifx=-3andy=5,whatisthevalueof2x-3y?A.-21B.-9C.9D.21E.394.Abagcontains5redmarbles,3bluemarbles,and4greenmarbles.Ifamarbleisselectedatrandom,whatistheprobabilitythatitisnotblue?A.3/12B.4/12C.5/12D.9/12E.8/125.Ifatraintravelsataconstantspeedof60milesperhour,howfarwillittravelin3.5hours?A.20.5milesB.210milesC.350milesD.420milesE.700miles6.Whatisthevalueoftheexpression3^2+4^2?A.7B.25C.35D.49E.817.If2x+3=11,whatisthevalueofx?A.4B.5C.6D.7E.88.Ashirtoriginallypricedat$40isonsalefor25%off.Howmuchisthediscount?A.$5B.$10C.$15D.$20E.$259.Iftheratioofboystogirlsinaclassis3:5,andthereare15boys,howmanygirlsarethere?A.5B.20C.25D.30E.4510.Whatistheleastcommonmultiple(LCM)of6and9?A.12B.18C.24D.27E.3611.Ifa=5andb=-2,whatisthevalueofa^2-b^2?A.7B.9C.11D.13E.1512.Astoresold30%ofitsinventoryinJanuaryand40%oftheremaininginventoryinFebruary.WhatpercentageoftheoriginalinventorywasleftattheendofFebruary?A.20%B.30%C.40%D.50%E.60%13.Ifanumberisincreasedby20%andthendecreasedby10%,whatistheoverallpercentagechangefromtheoriginalnumber?A.8%increaseB.8%decreaseC.10%increaseD.10%decreaseE.28%decrease14.Howmanypositiveintegersarefactorsof12?A.3B.4C.6D.8E.1215.If5x-7=3x+9,whatisthevalueofx?A.-8B.-2C.2D.4E.816.Arectanglehasalengththatistwiceitswidth.Iftheperimeteroftherectangleis30cm,whatisthewidthoftherectangleincentimeters?A.5B.7.5C.10D.15E.2017.Iftheaverage(arithmeticmean)ofthreenumbersis6,andtwoofthenumbersare4and8,whatisthethirdnumber?A.2B.4C.6D.8E.1018.Whichofthefollowingfractionsisequivalentto0.6?A.3/5B.4/5C.5/6D.6/10E.7/1019.Arecipecallsfor3/4cupofsugartomake2dozencookies.Howmuchsugarisneededtomake3dozencookies?A.1/2cupB.3/4cupC.11/4cupsD.11/2cupsE.2cups20.Ify=3x+2andx=-1,whatisthevalueofy?A.-1B.1C.4D.5E.721.Acartravels180milesusing6gallonsofgasoline.Howmanymilespergallonisthecar'sfuelefficiency?A.15B.30C.45D.60E.9022.If|x|=4andx<0,whatisthevalueofx?A.-1B.-2C.-4D.2E.423.Aboxcontains10redballsand8blueballs.Ifaballisdrawnatrandomandnotreplaced,whatistheprobabilityofdrawingablueballontheseconddraw?A.8/18B.8/17C.10/18D.10/17E.18/2624.IftheGCD(greatestcommondivisor)oftwonumbersis12andtheirLCM(leastcommonmultiple)is72,whatistheproductofthetwonumbers?A.24B.36C.48D.84E.14425.Whichofthefollowingisasolutiontotheinequality3x-5>7?A.-3B.-1C.1D.3E.526.Ifa=1/3andb=1/4,whatisthevalueofa+b?A.1/7B.3/7C.4/7D.7/12E.12/727.Astoreishavinga30%offsale.Ashirtthatoriginallycost$50ispurchasedduringthesale.Howmuchispaidfortheshirt?A.$10B.$20C.$30D.$40E.$50試卷答案1.C解析思路：設(shè)該數(shù)為y。根據(jù)題意，3y=18。解得y=18/3=6。然后計(jì)算5y=5*6=30。2.C解析思路：根據(jù)減法的性質(zhì)，(y+4)-(y-7)=y+4-y+7=4+7=11。也可以用分配律：(y+4)-(y-7)=y+4-y+7=11。3.A解析思路：將x=-3和y=5代入表達(dá)式2x-3y。得到2*(-3)-3*5=-6-15=-21。4.C解析思路：總共有5+3+4=12個(gè)marble。不是藍(lán)色marbles的數(shù)量是12-3=9個(gè)。概率=(不是藍(lán)色的數(shù)量)/(總數(shù)量)=9/12。該分?jǐn)?shù)可以約分為3/4。5.D解析思路：距離=速度*時(shí)間。距離=60miles/hour*3.5hours=210miles。6.B解析思路：計(jì)算3^2=9和4^2=16。然后將結(jié)果相加：9+16=25。7.C解析思路：根據(jù)等式的性質(zhì)，將等式兩邊同時(shí)減去3：2x+3-3=11-3。得到2x=8。然后將等式兩邊同時(shí)除以2：x=8/2=4。8.B解析思路：折扣金額=原價(jià)*折扣百分比。折扣金額=$40*25%=$40*0.25=$10。9.B解析思路：設(shè)女孩人數(shù)為g。根據(jù)比例關(guān)系，3/5=15/g。交叉相乘得到3g=5*15=75。解得g=75/3=25。10.B解析思路：6的倍數(shù)有：6,12,18,24,30,...。9的倍數(shù)有：9,18,27,36,...。它們的最小公倍數(shù)是18。11.D解析思路：將a=5和b=-2代入表達(dá)式a^2-b^2。得到5^2-(-2)^2=25-4=21。注意：a^2-b^2=(a+b)(a-b)。所以(5+(-2))(5-(-2))=(3)(7)=21。12.A解析思路：假設(shè)原始庫(kù)存為100單位。Januarysold:100*30%=30units.Remaining:100-30=70units.Februarysold:70*40%=28units.Leftatend:70-28=42units.Percentageleft=(42/100)*100%=42%。13.B解析思路：方法一：設(shè)原數(shù)為100。增加20%后變?yōu)?00*1.20=120。再減少10%后變?yōu)?20*0.90=108。變化百分比=(108-100)/100*100%=8%increase。方法二：設(shè)原數(shù)為x。最終數(shù)值為x*1.20*0.90=1.08x。變化百分比=(1.08x-x)/x*100%=0.08*100%=8%increase。14.C解析思路：12的正因數(shù)有：1,2,3,4,6,12。共有6個(gè)。15.E解析思路：根據(jù)等式的性質(zhì)，將等式兩邊同時(shí)減去3x：5x-7-3x=3x+9-3x。得到2x-7=9。然后將等式兩邊同時(shí)加上7：2x-7+7=9+7。得到2x=16。然后將等式兩邊同時(shí)除以2：x=16/2=8。16.A解析思路：設(shè)寬度為w。則長(zhǎng)度為2w。周長(zhǎng)=2*(長(zhǎng)度+寬度)=2*(2w+w)=6w。根據(jù)題意，6w=30cm。解得w=30/6=5cm。17.D解析思路：平均數(shù)=(a+b+c)/3。根據(jù)題意，6=(4+8+c)/3。解得18=12+c。所以c=18-12=6。18.A解析思路：將小數(shù)0.6轉(zhuǎn)換為分?jǐn)?shù)。0.6=6/10。然后將分?jǐn)?shù)約分。6/10=(6/2)/(10/2)=3/5。19.D解析思路：制作2dozen(24)cookies需要3/4cupsugar。比例關(guān)系：Sugar/Cookies=(3/4)/24=3/(4*24)=3/96=1/32。制作3dozen(36)cookies需要的sugar=(36/24)*(3/4)cups=(3/2)*(3/4)cups=9/8cups=11/8cups?；蛘撸幢壤黾樱涸黾?dozen(12)cookies，需要增加(12/24)*(3/4)=1/2*3/4=3/8cups。所以總量為3/4+3/8=6/8+3/8=9/8cups。20.D解析思路：將x=-1代入方程y=3x+2。得到y(tǒng)=3*(-1)+2=-3+2=-1。21.B解析思路：燃料效率（milespergallon）=總距離/總汽油量。效率=180miles/6gallons=30miles/gallon。22.C解析思路：絕對(duì)值|x|表示x到0的距離。因?yàn)閨x|=4