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2、 f(x) ax bx 3x1在xf (x)32f和f(f(x) 16)y f(x)(x ,xb,t),f(x)abta2x1 ,nR,m0，f (x) mx 3(m 1)x nx 132m與 nf(x) y f(x)3mmxf(x) x bx cx2,f (x)32 f (x) 3xbx .2M( f(6x y7 06 f( 7 0,即f( f ( 6.3bc bc 即解得b c 3.1bc2 1. bc x 3x 3x2. f (x)32 f (x) 3x 6x 3. 令 即 3x 6x 3 x 2x 1 0.2221 2,x 1 2. 當x 1 2,或x 1 , f (x) x12當1

3、2 x 1 , f (x) 0.故 在 f (x) x 3x 3x 2 ( 2)32在 2,1 2) 2,) f (x) ax bx 3f f ( 02ab3 a b0.ab3 0. x 3x, f (x) 3x 3 xxf (x).32 令f (x) 0 x x 1.若x(, )f (x) 0，故f(x)在(, 若x( f(x) )在f (x)0f(x) ( f(2在f 2 x 3xy 16)3 x 3xM(x , y ) My.30因f (x ) x y y000 x x x )0 2200000(x 3x ) x x )16302000 x30M(8x 2.0 2)9xy160. x x

4、)t(x x x txt,f (x)232 f (x) 3x2 2x t.若f(x(,(上可設(shè)f (x) 0.f(x)當且僅當f t 1且f ( t 5時( ( ( ) 0,即 ( (.f x f x f x故tt ( ) 3x nx6( 1) 1 ( ) f x f xmx2m(1)03 1) 03 6n m f mmn 2 ( )3m x m = m x x6( 1) 3 6 3 ( 1) 1 f xmx2 m20時，有11xf(x) f(x)與當mm222 x10m( )f x0000f(x)20 f(x)在,1mm2 ,1)(1,)在m( )3m x2( 1) 20 f xmmx22222 又m0 x (mx 0 x (mx 0,x 1,12即2mmmm12g(x) x )x設(shè)2mm2 2g(1)012 0m m