輸入一個(gè)五位正整數(shù)，求出該數(shù)的各位數(shù)字。#include<stdio.h>voidmain(){inta,b,c,d,e,f;scanf("%d",&a);b=a/10000;c=a/1000%10;d=a/100%10;e=a/10%/10;f=a/10;printf("b=%d,c=%d,d=%d,e=%d,f=%d\n",b,c,d,e,f)；}從鍵盤輸一個(gè)三位數(shù)，將它們逆序輸出。#include<stdio.h>voidmain(){inta,b;scanf("%d",&a);b=a/100+a/10%10*10+a%10*100;printf("b=%d\n",b);}3?已知雞兔共有a個(gè)頭，有腳b只，計(jì)算雞兔各是多少只？#include<stdio.h>voidmain(){inta,b,x,y;scanf("%d,%d",&a,&b);x=(b-2*a)/2;y=(4*a-b)/2;printf("x=%d,y=%d\n",x,y);}輸入四個(gè)整數(shù)，要求按大小順序輸出。#include<stdio.h>voidmain(){inta,b,c,e,t;scanf("%d,%d,%d,%d",&a,&b,&c,&e);if(a>b){a=t,t=b,b=a;}if(a>c){a=t,t=c,c=a;}if(a>e){a=t,t=e,e=a;}if(b>c){b=t,t=c,c=b;}if(b>e){b=t,t=e,e=b;}if(c>e){c=t,t=e,e=t;}printf("%d,%d,%d,%d\n",a,b,c,e);}輸入三角形的三條邊，判斷那否構(gòu)成三角形，如果能，則計(jì)算三角形的面積并判斷三角形的類型。#include<stdio.h>#include<math.h>voidmain(){floata,b,c,s,area;scanf("%f,%f,%f"&a,&b,&c);if(a+b>c&&a+c>b&&b+c>a){s=(a+b+c)*0.5;area=sqrt(s*(s-a)*(s-b)*(s-c));printf("%f\n",area);if(a*a+b*b>c*c||a*a+c*c>b*b||b*b+c*c>a*a)printf("銳角三角形")elseif(a*a+b*b<c*c||a*a+c*c<b*b||b*b+c*c<a*a)printf("鈍角三角形")elseif(a*a+b*b==c*c||a*a+c*c==b*b||b*b+c*c==a*a)printf("直角三角形")}elseprintf("不能構(gòu)成順三角形")}求一元二次方程ax2+bx+c=0的根，其中a,b,c可以是任意實(shí)數(shù)，要求從鍵盤輸入#include<math.h>main(){floata,b,c,d,x1,x2,lp,ip;scanf("%f%f%f",&a,&b,&c);;printf("theequation");if(fabs(a)<1e-6)printf("isnotquadratic");else{d=b*b-4*a*c;if(fabs(a)<=1e-6){printf("hastwoequalroot:\n");printf("x1=x2=%8.4f\n",-b/(2*a));}elseif(d>1e-6){x1=(-b+sqrt(d)/(2*a);x2=(-b-sqrt(d)/(2*a);printf("hastworealroot:\n);printf("x1=%8,4f,x2=%8.4f\n",x1,x2);else{lp=-b/(2*a);ip=sqrt(-d)/(2*a);printf("hastwocomplexroot:\n");printf("x1=%8.4f+%8.4fi\n",lp,ip);printf("x2=%8.4f-%8.4fi\n",lp,ip);}}}實(shí)現(xiàn)輸入年，月，日，求這一年是該年中的第幾天。#include<stdio.h>voidmain(){inta,b,c,d;scanf("%d,%d,%d",&a,&b,&c);printf("%d年％宀月％d日\(chéng)n",a,b,c);if(b==1)d=c;elseif(b==2)d=31+c;elseif(b==3)d=59+c;elseif(b==4)d=89+c;elseif(b==5)d=120+c;elseif(b==6)d=150+c;elseif(b==7)d=181+c;elseif(b==8)d=212+c;elseif(b==9)d=242+c;elseif(b==10)d=273+c;elseif(b==11)d=304+c;elseif(b==12)d=334+c;if(a%4==0&&a%100!=0||a%400==0&&b>2){d=d+1;printf("%d\n",d}elseprintf("%d\n",d);}&輸入一年，判斷是否閏年，如果是，輸出yes,否則輸出no#include<stdio.h>voidmain(){inta;printf("Input:");scanf("%d",&a);if((a%4==0&&a%100!=0)||a%400==0)printf("YES\n");elseprintf("NO\n");}輸出2000到2005所有的閏年并統(tǒng)計(jì)個(gè)數(shù)，按每五個(gè)的格式輸出#include<stdio.h>voidmain(){inta,b=0,c,d;printf("輸入介于的兩年：")；scanf("%d,%d",&c,&d);for(a=c;a<=d;a++){if((a%4==0&&a%100!=0)||a%400==0){printf("%6d",a);b=b+1;}if(b%5==0)printf("\n");}printf("\n閏年有%d個(gè)。\n",b);}輸入一個(gè)數(shù)M,判斷是否是素?cái)?shù)，如果是輸出yes,否輸出no.#include<stdio.h>#include<math.h>voidmain(){intn,i,j=1;floata;printf("Inputnumberm：");scanf("%d",&n);a=sqrt((double)n);for(i=2;i<=a;i++)if(n%i==0){j=0;break;}if(j)printf("YES\n");elseprintf("NO\n");}輸出100到200所有的素?cái)?shù)。#include<stdio.h>#include<math.h>voidmain(){intn,i,a,b,c,j,k=0;printf("Inputnumber(n,m):");scanf("%d,%d",&a,&b);for(n=a;n<=b;n++){j=1;c=sqrt((double)n);for(i=2;i<=c;i++)if(n%i==0){j=0;break;}if(j){printf("%d\n",n);k++;}}printf("素?cái)?shù)%d個(gè)\n",k);}輸入一個(gè)數(shù)N,球1+2+。。。+N#include<stdio.h>voidmain(){intn,sum=0,i;printf("Inputn:");scanf("%d",&n);for(i=1;i<=n;i++)sum=sum+i;printf("1+2+3+ +n=%d\n",sum);}輸入一個(gè)數(shù),求N!#include<stdio.h>voidmain(){intn,sum=1,i;printf("Inputn:");scanf("%d",&n);for(i=1;i<=n;i++)sum=sum*i;printf("n!=%d\n",sum);}輸入一個(gè)數(shù)，分別球1!2!...#include<stdio.h>voidmain(){intn,sum,i,j;printf("Inputn:");scanf("%d",&n);printf("1!,2!,3! n!分別為：\n");for(i=1;i<=n;i++){sum=1;for(j=1;j<=i;j++)sum=sum*j;printf("%6d\n",sum);}}輸入一個(gè)數(shù)N求1！+2！+。。。#include<stdio.h>voidmain(){intn,sum,i,j,s=0;printf("Inputn：");scanf("%d",&n);printf("l!+2!+3!+ +n!=");for(i=1;i<=n;i++){sum=1;for(j=1;j<=i;j++)sum=sum*j;s=s+sum;}printf("%d\n",s);}輸入一個(gè)數(shù)n,求l/l!+l/2!+...#include<stdio.h>voidmain(){intn,i=1,j;floatsum=0,b,a,s=1;printf("Inputn：");scanf("%d",&n);while(i<=n){a=1;for(j=1;j<=i;j++)a=a*j;b=s/a;sum=sum+b;i++;}printf("結(jié)果%f\n",sum,b);}打印fibbonacci數(shù)列的前20項(xiàng)#include<stdio.h>voidmain(){longinta,b=0,c=1,n;printf("輸入要輸出的項(xiàng)數(shù):")；scanf("%d",&n);for(a=0;a<n;++a){if(a%5==0)printf("\n");printf("%d\t",c);c+=b;b=c-b;}printf("\n");}求水仙花數(shù)#include<stdio.h>voidmain(){inti,j,k,n;printf("水仙花數(shù)有:");for(i=1;i<10;i++)for(j=0;j<10;j++)for(k=0;k<10;k++){n=i*100+j*10+k;if(n==((i*i*i)+(j*j*j)+(k*k*k)))printf("%d\t",n);}}母牛生小牛#include<stdio.h>voidmain(){inti,n,f1=1,f2=0,f3=0,f4=0;printf("輸入年：")；scanf("%d",&n);for(i=2;i<=n;i++){f4=f4+f3;f3=f2;f2=f1;f1=f4;}printf("現(xiàn)在有％d頭牛。\n",fl+f2+f3+f4);}迭代法求a的平方根#include<stdio.h>#include<math.h>voidmain(){floatx0,f,x=1,a;printf("Inputa：");scanf("%f",&a);do{x0=x;f=(x0+a/x0)/2;x=f;}while(fabs(x-x0)>=1e-5);printf("%f\n",x);}完整九九表#include<stdio.h>voidmain(){inti,j;for(i=1;i<=9;i++){for(j=1;j<=9;j++)printf("%dX%d=%-4d",i,j,i*j);printf("\n");}}左下#include<stdio.h>voidmain(){inti,j;for(i=1;i<=9;i++){for(j=1;j<=i;j++)printf("%dX%d=%-4d",i,j,i*j);printf("\n");}}右上#include<stdio.h>voidmain(){inti,j,x;for(i=1;i<=9;i++){for(x=i-1;x>=1;x--)printf("\t");for(j=i;j<=9;j++){printf("%d*%d=%d\t",i,j,i*j);}printf("\n");}}右下#include<stdio.h>voidmain(){inti,j,x;for(i=1;i<=9;i++){for(x=9-i;x>=1;x--)printf("\t");for(j=10-i;j<=9;j++){printf("%d*%d=%d\t",i,j,i*j);}printf("\n");}}左上#include<stdio.h>voidmain(){inti,j;for(i=1;i<=9;i++){for(j=1;j<=10-i;j++)printf("%d*%d=%d\t",i,j,i*j);printf("\n");}}百元買百雞#include<stdio.h>voidmain(){intx,y,z;for(x=0;x<=100;x++)for(y=0;y<=100;y++){z=100-x-y;if(15*x+9*y+z==300)printf("公雞％d，母雞％d,小雞％d\n",x,y,z);}}搬磚#include<stdio.h>voidmain(){intx,y,z;for(x=0;x<=36;x++)for(y=0;y<=36;y++){z=36-y-x;if(8*x+6*y+z==72)printf("男%d,女%d,小孩％d\n",x,y,z);}}由小到大排序、#defineN10#include<stdio.h>voidmain(){inti,j,k,a[N],t;printf("Inputnumbers:");for(i=0;i<N;i++)scanf("%d",&a[i]);printf("\n");for(i=0;i<N-1;i++){k=i;for(j=i+1;j<N;j++)if(a[j]<a[k])k=j;if(i!=k){t=a[k];a[k]=a[i];a[i]=t;}}for(i=0;i<N;i++)printf("%d",a[i]);}由大到小、#defineN10#include<stdio.h>voidmain(){inti,j,k,a[N],t;printf("Inputnumbers:");for(i=0;i<N;i++)scanf("%d",&a[i]);printf("\n");for(i=0;i<N-1;i++){k=i;for(j=i+1;j<N;j++)if(a[j]>a[k])k=j;if(i!=k){t=a[k];a[k]=a[i];a[i]=t;}}for(i=0;i<N;i++)printf("%d",a[i]);}冒泡法由小到大#defineN10#include<stdio.h>voidmain(){inta[N],i,j,t;printf("Input:");for(i=0;i<N;i++)scanf("%d",&a[i]);for(i=0;i<N-1;i++)for(j=0;j<N-1;j++)if(a[j]>a[j+1]){t=a[j];a[j]=a[j+1];a[j+1]=t;}printf("從小到大:")；for(i=0;i<N;i++)printf("%d",a[i]);printf("\n");}冒泡法由大到小、#defineN10#include<stdio.h>voidmain(){inta[N],i,j,t;printf("Input:");for(i=0;i<N;i++)scanf("%d",&a[i]);for(i=0;i<N-1;i++)for(j=0;j<N-1;j++)if(a[j]<a[j+1]){t=a[j];a[j]=a[j+1];a[j+1]=t;}printf("從大到小:");for(i=0;i<N;i++)printf("%d",a[i]);printf("\n");}一維數(shù)組逆置重放、#defineN10#include<stdio.h>voidmain(){inta[N],t,i;for(i=0;i<N;i++)scanf("%d",&a[i]);for(i=0;i<(N/2);i++){t=a[i];a[i]=a[N-1-i];a[N-1-i]=t;}for(i=0;i<N;i++)printf("%d",a[i]);printf("\n");}最大值并記下位置、#defineN10#include<stdio.h>voidmain(){intmax,a[N],i,x=0;for(i=0;i<N;i++)scanf("%d",&a[i]);max=a[0];for(i=1;i<N;i++)if(max<a[i]){max=a[i];x=i;}printf("最大為％宀,第％宀個(gè)。",max,x+l);}最小值及位置、#defineN10#include<stdio.h>voidmain(){intmin,a[N],i,x=0;for(i=0;i<N;i++)scanf("%d",&a[i]);min=a[0];for(i=1;i<N;i++)if(min>a[i]){min=a[i];x=i;}printf("最小為％宀,第％宀個(gè)。",min,x+l);}數(shù)組平均值并輸出大于平均值的數(shù)、#defineN10#include<stdio.h>voidmain(){inta[N],i;floatave,sum=0;for(i=0;i<N;i++)scanf("%d",&a[i]);for(i=0;i<N;i++)sum=sum+a[i];ave=sum/N;printf("平均值為%f,大于平均的數(shù)有:",ave);for(i=0;i<N;i++)if(a[i]>ave)printf("%d",a[i]);}數(shù)組平均值并輸出小于平均值的數(shù)、#defineN10#include<stdio.h>voidmain(){inta[N],i;floatave,sum=0;for(i=0;i<N;i++)scanf("%d",&a[i]);for(i=0;i<N;i++)sum=sum+a[i];ave=sum/N;printf("平均值為％f,小于平均的數(shù)有:",ave);for(i=0;i<N;i++)if(a[i]<ave)printf("%d",a[i]);}用數(shù)組的方法打印fibbonacci、#include<stdio.h>voidmain(){longinta[20]={1,1},i;for(i=2;i<20;i++)a[i]=a[i-1]+a[i-2];for(i=0;i<20;i++){printf("%6d",a[i]);if((i+1)%5==0)printf("\n");}}輸入3行4列矩陣，找最大值、#include<stdio.h>voidmain(){inta[3][4],i,j,max;printf("Inputnumbers:");for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%d",&a[i][j]);printf("\n");for(i=0;i<3;i++)for(j=0;j<4;j++){printf("%4d",a[i][j]);if(j==3)printf("\n");}max=a[0][0];for(i=0;i<3;i++)for(j=0;j<4;j++)if(max<a[i][j]){max=a[i][j];}for(i=0;i<3;i++)for(j=0;j<4;j++)if(max==a[i][j])printf("%d行,％d歹山最大％d\n",i+l,j+l,max);輸入3行4列矩陣，找最小值#include<stdio.h>voidmain(){inta[3][4],i,j,max;printf("Inputnumbers:");for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%d",&a[i][j]);printf("\n");for(i=0;i<3;i++)for(j=0;j<4;j++){printf("%4d",a[i][j]);if(j==3)printf("\n");}max=a[0][0];for(i=0;i<3;i++)for(j=0;j<4;j++)if(max>a[i][j]){max=a[i][j];}for(i=0;i<3;i++)for(j=0;j<4;j++)if(max==a[i][j]),j+1,max);printf("%d行,％d列，最小％d\n",},j+1,max);磚置矩陣(3行4列)#include<stdio.h>voidmain(){inti,j,a[3][4],b[4][3];printf("Input:");for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%d",&a[i][j]);printf("轉(zhuǎn)置前：\n");for(i=0;i<3;i++){for(j=0;j<4;j++)printf("%4d",a[i][j]);printf("\n");}for(i=0;i<3;i++)for(j=0;j<4;j++)b[j][i]=a[i][j];printf("轉(zhuǎn)置后:\n");for(i=0;i<4;i++){for(j=0;j<3;j++)printf("%4d",b[i][j]);printf("\n");}}轉(zhuǎn)置矩陣(3行3列)#include<stdio.h>voidmain(){inti,j,t,a[3][3];printf("Input:");for(i=0;i<3;i++)for(j=0;j<3;j++)scanf("%d",&a[i][j]);printf("轉(zhuǎn)置前：\n");for(i=0;i<3;i++){for(j=0;j<3;j++)printf("%4d",a[i][j]);printf("\n");}for(i=0;i<3;i++)for(j=i+1;j<3;j++){t=a[i][j];a[i][j]=a[j][i];a[j][i]=t;}printf("轉(zhuǎn)置后:\n");for(i=0;i<3;i++){for(j=0;j<3;j++)printf("%4d",a[i][j]);printf("\n");}}42.3行3列陣，按行列式輸出，求對(duì)角線元素之和#include<stdio.h>voidmain(){inti,j,t,a[3][3];printf("Input:");for(i=0;i<3;i++)for(j=0;j<3;j++)scanf("%d",&a[i][j]);printf("轉(zhuǎn)置前:\n");for(i=0;i<3;i++){for(j=0;j<3;j++)printf("%4d",a[i][j]);printf("\n");}for(i=0;i<3;i++)for(j=i+1;j<3;j++){t=a[i][j];a[i][j]=a[j][i];a[j][i]=t;}printf("轉(zhuǎn)置后:\n");for(i=0;i<3;i++){for(j=0;j<3;j++)printf("%4d",a[i][j]);printf("\n");}}43.3行4列陣，求周邊元素之和#include<stdio.h>voidmain(){inta[3][4],i,j,sum=0;printf("Input:");for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%d",&a[i][j]);for(i=0;i<3;i++){for(j=0;j<4;j++)printf("%5d",a[i][j]);printf("\n");}for(i=0;i<3;i++)for(j=0;j<4;j++)if(i==0||i==2||j==0||j==3)sum=sum+a[i][j];printf("周邊和為％d\n",sum);}44.3行4列陣，求周邊元素之平均值#include<stdio.h>voidmain(){inta[3][4],i,j;floatsum=0,ave;printf("Input:");for(i=0;i<3;i++)for(j=0;j<4;j++)scanf("%d",&a[i][j]);for(i=0;i<3;i++){for(j=0;j<4;j++)printf("%5d",a[i][j]);printf("\n");}for(i=0;i<3;i++)for(j=0;j<4;j++)if(i==0||i==2||j==0||j==3)sum=sum+a[i][j];printf("周邊和為％f\n",sum);ave=sum/10;printf("平均值為％f\n",ave);}左對(duì)齊的楊輝三角#include<stdio.h>voidmain(){inta[10][10],i,j;for(i=0;i<10;i++){a[i][0]=1,a[i][i]=1;}for(i=2;i<10;i++)for(j=1;j<i;j++)a[i][j]=a[i-1][j-1]+a[i-1][j];for(i=0;i<10;i++){for(j=0;j<=i;j++)printf("%5d",a[i][j]);printf("\n");}}中對(duì)齊的楊輝三角#include<stdio.h>voidmain(){inta[10][10],i,j;for(i=0;i<10;i++){a[i][0]=1,a[i][i]=1;}for(i=2;i<10;i++)for(j=1;j<i;j++)a[i][j]=a[i-1][j-1]+a[i-1][j];for(i=0;i<10;i++){for(j=1;j<=10-i;j++)printf("");for(j=0;j<=i;j++)printf("%3d",a[i][j]);printf("\n");}輸入一行字符，統(tǒng)計(jì)個(gè)數(shù)#include<stdio.h>voidmain(){charstr[100],a,b;inti,num;printf("Inputthetextline:");gets(str);a='';num=0;i=0;while(str[i]!='\0'){b=str[i];if((b!=''||b!=','||b!=';'||b!='!'||b!='.')&&(a==''||a==','||a==';'||a=='!'||a=='.'))num++;a=b;i++;}printf("\nThenumberofwordsis:%d\n",num);}輸出國(guó)家名#include<stdio.h>voidmain(){chara[20],b[20];inti,k,j;printf("Input:");gets(a);gets(b);for(i=0;i<20;i++)if(a[i]=='\0')break;for(j=0;j<20;j++)if(b[j]=='\0')break;for(k=0;k<=j;k++){a[i]=b[k];i++;}printf("%s\n",a);}判斷素?cái)?shù)的函數(shù)#include<stdio.h>intpan(int);voidmain(){inta;printf("Inputmunber:");scanf("%d",&a);if(pan(a))printf("Yes\n");elseprintf("No\n");}intpan(intb){inti,c;c=b/2;for(i=2;i<=c;i++)if(b%i==0)break;if(i>c)return(1);elsereturn(0);}寫函數(shù)，在主函數(shù)中輸入二維數(shù)組，通過(guò)調(diào)用函數(shù)，輸出轉(zhuǎn)置后的矩陣#include<stdio.h>voidz(intc[4][4]){inti,j,t;for(i=0;i<4;i++)for(j=i+1;j<4;j++){t=c[i][j];c[i][j]=c[j][i];c[j][i]=t;}}voidmain(){inta[4][4],h,f;printf("Inputnumbers:");for(h=0;h<4;h++)for(f=0;f<4;f++)scanf("%d",&a[h][f]);printf("Beforechange\n");for(h=0;h<4;h++){for(f=0;f<4;f++)printf("%5d",a[h][f]);printf("\n");}printf("Afterchange\n");z(a);for(h=0;h<4;h++){for(f=0;f<4;f++)printf("%5d",a[h][f]);printf("\n");}}寫兩個(gè)函數(shù)，求他們的最大公約數(shù)和最小公倍數(shù)#include<stdio.h>intb(inta,intb){inti,Min=a>b?a:b;for(i=Min;;i++)if(i%a==0&&i%b==0){Min=i;break;}returnMin;}inty(inta,intb){inti,Max;for(i=(a>b?a:b);;i--)if(a%i==0&&b%i==0){Max=i;break;}returnMax;}voidmain(){intc,d;prin