(完整版)初中數學分式計算題及答案

分式計算題精選1.計算$x+y$。2.化簡$\dfrac{a^2+4a}{a+2}+\dfrac{2a}{a+2}$，其結果是$\dfrac{a^2+6a}{a+2}$。3.化簡$\dfrac{x^2-4}{4x-16}$。4.化簡$\dfrac{3x^2-15x}{6x^2-18x}$。5.化簡$\dfrac{x^2+4x+4}{x^2-4}$。6.計算$\dfrac{2x-1}{x+1}+\dfrac{2x+1}{x-1}$。7.化簡$\dfrac{a^2-1}{a^2+1}-\dfrac{a}{a+1}$。8.化簡$\dfrac{3}{2x-2}-\dfrac{2}{3x-3}$。9.化簡$\dfrac{a^2-4a+4}{a^2-4}-\dfrac{a-2}{a+2}$。10.計算$\dfrac{2}{x+1}-\dfrac{3}{x-2}$。11.計算$\dfrac{2x^2+5x-3}{x^2-4x+3}\div\dfrac{x^2-3x}{x^2-2x-3}$。12.解方程$\dfrac{2}{x-1}+\dfrac{3}{x+2}=\dfrac{1}{x}$。13.解方程$\dfrac{2x-1}{x-2}+\dfrac{3x+1}{x+1}=4$。14.解方程$\dfrac{x}{x+1}+\dfrac{x+1}{x}=\dfrac{10}{3}$。15.解方程$\dfrac{x-1}{x+2}+\dfrac{2x+1}{x-1}=0$。16.已知$a,b,c$為實數，且滿足$\dfrac{b-3}{a-b}=\dfrac{c-2}{a-c}$，求$\dfrac{11a}{b-c}$的值。17.解方程$\dfrac{x-1}{x+1}+\dfrac{2x+3}{x-2}=\dfrac{2x-1}{x-1}$。18.解方程$\dfrac{x+1}{x-1}-\dfrac{x-1}{x+1}=1$。19.已知$x,y$滿足$3x+xy-2y=0$，求$\dfrac{x-y}{y-x}$的值。20.已知$\dfrac{x}{y}+\dfrac{y}{x}=3$，求$\dfrac{x^2-y^2}{xy}$的值。21.計算$\dfrac{x+1}{2x-2}-\dfrac{2x-1}{1-x}$。22.解方程組$\begin{cases}x-y=3\\2x+2y=9\end{cases}$。23.計算$\dfrac{x^2-1}{2x-2}+\dfrac{x^2+1}{2x+2}$，其中$x\neq1$。24.計算$\dfrac{a^2+2a+1}{a^2-1}-\dfrac{a^2-2a+1}{a^2+1}$。25.計算$\dfrac{1}{1+\dfrac{1}{2+\dfrac{1}{4}}}+\dfrac{1}{4+\dfrac{1}{2+\dfrac{1}{1}}}$。刪除明顯有問題的段落，改寫文章如下：解方程：（1）x^2-x-2=0；（2）x^2-x=0。（1）方程兩邊同乘(x-2)(x+1)，得(x+1)^2+x-2=(x-2)(x+1)，化簡后得x=-3。經檢驗，x=-3是原方程的解。（2）方程兩邊同乘x(x-1)，得3x-(x+2)=0，解得x=1。經檢驗，x=1是原方程的解。（1）x(x-1)(x+1)=4，化簡