1、C語(yǔ)言課程設(shè)計(jì)報(bào)告（銷售管理系統(tǒng)）學(xué)院:班級(jí):學(xué)號(hào):姓名:目錄一、銷售管理系統(tǒng)的設(shè)計(jì)目的 3二、需求分析 4三、概要設(shè)計(jì) 5四、訐細(xì)設(shè)計(jì) 6五、主要原程序代碼 8六、試分析過(guò)程描述調(diào)16七、總結(jié) 17、銷售管理系統(tǒng)的設(shè)計(jì)目的1、通過(guò)本課程設(shè)計(jì)，培養(yǎng)上機(jī)動(dòng)手能力，使學(xué)生鞏固 C語(yǔ)言程序設(shè)計(jì)課程學(xué)習(xí)的內(nèi)容，掌握工程軟件設(shè)計(jì)的基本 方法，強(qiáng)化上機(jī)動(dòng)手能力，闖過(guò)編程關(guān)；2、學(xué)會(huì)用c語(yǔ)言程序設(shè)計(jì)來(lái)設(shè)計(jì)銷售管理系統(tǒng)設(shè)計(jì);3、為后續(xù)各門計(jì)算機(jī)課程的學(xué)習(xí)打下堅(jiān)實(shí)基礎(chǔ)。二、需求分析1) 設(shè)計(jì)題目分析 題目：銷售管理系統(tǒng)2) 設(shè)計(jì)要求分析（1）用C語(yǔ)言實(shí)現(xiàn)程序設(shè)計(jì)（2）利用結(jié)構(gòu)體進(jìn)行相關(guān)信息處理 （3）畫出查詢模

2、塊的流程圖 （4）系統(tǒng)的各個(gè)功能模塊要求用函數(shù)的形式實(shí)現(xiàn)（5）界面友好（良好的人機(jī)互交），程序要有注釋。3）系統(tǒng)功能需求分析（1）計(jì)算上個(gè)月每個(gè)人每種產(chǎn)品的銷售額（2）按銷售額對(duì)銷售員進(jìn)行排序，輸出排序結(jié)果（銷售員代號(hào)）（3）統(tǒng)計(jì)每種產(chǎn)品的總銷售額，對(duì)這些產(chǎn)品按從高到低的順序，輸出排序結(jié)果（需輸出產(chǎn)品的代號(hào)和銷售額）（4）輸出統(tǒng)計(jì)報(bào)表三、概要設(shè)計(jì)1）總體設(shè)計(jì)本程序要設(shè)計(jì)銷售管理系統(tǒng)，首先要設(shè)計(jì)一個(gè)選擇函數(shù)，用來(lái)選擇運(yùn)行其他各個(gè)函數(shù)。接著要分別設(shè)計(jì)輸入數(shù)據(jù)函數(shù)，各種統(tǒng)計(jì)函數(shù)和各種排序函數(shù)，用以實(shí)現(xiàn)各種統(tǒng)計(jì)和排序功能，最后要設(shè)計(jì)一個(gè)數(shù)據(jù)請(qǐng)空函數(shù)和統(tǒng)計(jì)表輸出函數(shù)，得 到程序設(shè)計(jì)要求的表格。2）系統(tǒng)流

3、程圖20四、詳細(xì)設(shè)計(jì)1）詳細(xì)設(shè)計(jì)思路(1) . main ()主函數(shù)設(shè):.了程序的流程,結(jié)束程序。(2) .fprintf ()選擇函數(shù)選擇所想運(yùn)行的各個(gè)函數(shù)(3) mulu()輸入函數(shù)輸入便條的數(shù)據(jù).(4) . arg ()文件的數(shù)據(jù)輸入函數(shù)多次輸入數(shù)據(jù)(5) .outputl ()統(tǒng)計(jì)函數(shù)每個(gè)人的每種產(chǎn)品銷售額的統(tǒng)計(jì)(6) . Output2 ()總額排序函數(shù)按銷售額對(duì)商品進(jìn)行排序(7) . output 3 ()總額統(tǒng)計(jì)函數(shù)統(tǒng)計(jì)每種產(chǎn)品的總額(8) . Output4 () 售員排序函數(shù)按照銷售額對(duì)售員排序函數(shù)(9) .save ()統(tǒng)計(jì)報(bào)表函數(shù)統(tǒng)計(jì)商品總額2)工作流程圖case 1;五

4、、主要源程序代碼1)源程序清單(1)計(jì)算每個(gè)人每種產(chǎn)品的銷售額。(2)按銷售額對(duì)銷售員進(jìn)行排序，輸出排序結(jié)果(銷售員代號(hào))(3)統(tǒng)計(jì)每種產(chǎn)品的總銷售額，按從高到底的順序，輸出排序結(jié)果(需輸出 產(chǎn)品代號(hào)，銷售額)/I. 首先，要定義每個(gè)人，每種產(chǎn)品，銷售額數(shù)組如inti,j,sumO=O,sum l=0,sum2=0,sum3=0,sum4=0,sum5=0;int c4,bl4=0,b24=0,b34=0,b44=0,b54=0,用 for 循環(huán)來(lái)求每個(gè)人的總銷售額：for(i=0;i<4;i+)；用for循環(huán)來(lái)求每個(gè)人每種產(chǎn)品的總銷售額：for(i=0;i<n;i+4-), fo

5、r(j=0;jv4;j+)；在用for循環(huán)每種產(chǎn)品的總銷售額：for(i=0;iv4;i+),之后則在系統(tǒng)界面輸入銷售員代號(hào)，產(chǎn)品代號(hào)，產(chǎn) 品代號(hào)用printf 即可實(shí)現(xiàn)，用sum對(duì)每個(gè)銷售員的銷售額求和，用system(”cls”) 來(lái)錄入信息，然后輸出頭標(biāo)(如銷售員代號(hào)，產(chǎn)品代號(hào)，銷售額等，用 printf 實(shí)現(xiàn))，之后開始查詢，用for語(yǔ)句來(lái)。2.此部分要分兩部分其一是，每位銷售員銷售額；其二是，按銷售額對(duì)銷售員排 序。在求每個(gè)銷售員銷售額時(shí)也是要先定義銷售員代號(hào)，產(chǎn)品代號(hào)，銷售額。接著是則是用輸入要查詢的銷售員的代號(hào)，用 scanfC%d;&s)來(lái)記錄輸入銷售 員代號(hào)的信息，然

6、后輸出頭標(biāo)(如銷售員代號(hào)，產(chǎn)品代號(hào)，銷售額等，用printf 實(shí)現(xiàn))，之后開始查詢，查詢信息首先需要一個(gè)for語(yǔ)句來(lái)，實(shí)現(xiàn)對(duì)已存入數(shù)據(jù) 的所有查詢for(i=0;i<n;i+), 關(guān)鍵內(nèi)容是查詢銷售員代號(hào)時(shí)用 if(strcmp(name,)=0),找出與輸入的銷售員相同的儲(chǔ)存信息，查找完成后則把該銷售員的所有信息全部輸出。上面是求每個(gè)銷售員銷售額，接著是要在上面的基礎(chǔ)上排序。首先要定義兩個(gè)數(shù)組如：intc4,m4,接著用 for循環(huán)(for(i=0;i<4;i+)； for(j=i+l;jv4;j+) )對(duì)銷售員的銷售額進(jìn)行排序，再用if語(yǔ)句來(lái)求，最后是輸出用pri

7、ntf(n%dnn,mi) 實(shí)現(xiàn)。 3.也一樣首先要定義數(shù)組，接著用ci=sum(t,n,i+l)求每個(gè)人的總銷售額，再用for循環(huán)，再用sumO-F=ci對(duì)所有產(chǎn)品的銷售額求總，用for循環(huán)對(duì)每個(gè)人每種產(chǎn) 品的銷售額求總銷售額，再用for循環(huán)實(shí)現(xiàn)每種產(chǎn)品的總銷售額，然后輸出頭標(biāo) (如銷售員代號(hào)，產(chǎn)品代號(hào)，總銷售額等，用printf實(shí)現(xiàn))即可。2)函數(shù)#include<stdio.h>#include<conio.h>#define max 620struct goodsint p_num;int num;int g_num; smax;struct personsin

8、t num7;)p6,w;int n;main() (int input(), output 1(),output2(),output3(),output4();int arg(),mulu();int save();printf(H nnn ttt 桂桂桂叮HE PROJECT甜麻桂媽nnn")；printf(nPlease input the informations :(over to 0)nnnn);printf("n");for(n=0;n<max;n+)scanfC%d”,&s n.p_num);if(sn.p_num=(O)break;

9、elsescanf(n%d%dH,&s n.g_num,&s n.num);printf("n");)mulu();int mulu()int choice;argO;do(printf(n nn ttt或HE PROJECT*nnn);printR"1 .count the g_mon of each goods every people products lastmonthnH);printf(n 2.putthe people in order by g_mon and output the result by p_numnH);printR

10、” 3.count the total g_mon,output the result in order from high to lownH);printf(n 4.output the report form of goods nnn);printf(n O.exit nnH);printf(n Please Choose (0-4):")；scanf(H%dM,&choice);switch(choice)(case 1: output! ();break;case 2: output2();break;case 3: output3();break;case 4: o

11、utput4();break;case 0: exit(O);)(while (choice !=0);int arg()(int k,a,j;for(k=l ;k<=5 ;k+)p0.numk=k;for(a=l;a<=6;a+)pk.numa =0;)for(k=l ;k<=4;k+)pk.num0=k;fbr(k=l ;k<=4;k+)for(a=l ;a<=5;a+)for(j=O;j<n;j+)if(s j.p_num=k && s j.g_num=a) pk.numa=pk.numa +sj.num;fbr(a=l ;a<=

12、5;a+)for(k=l ;k<=4;k+)p5.numa =p5.numa +pk.numa;for(k=l;k<=5;k+)for(a=l;a<=5;a+)pk.num6=pk.num6+pk.numa;int outputl() int i,k;conditionof everyone'sg mon lastDm o n th :*叭 nn ");printR“g_num np_numtn);for(k=l ;k<=5 ;k+)printf("dt”,pO.numk); printf("nnu);fbr(i=l ;i<=

13、4;i+)(fbr(k=O;k<=5;k+)printf(M%dtn,pi.numk);printfCXn1');)mulu();int output2()(int i,r,j;fbr(i=l ;i<4;+i)(r=i；for(j=i+l;j<=4;j4-+)if(pr.num6<pj.num6)Eif(r!=i)w=pi;pi=pr； pr=w;) printf(1 fnnnnnn*0rder of people by goods* sum*nn");printf(np_num tsum_mon n")；fbr(i=l ;i<=4;i

14、+)printf(n %dtt %dn",pi.num0,pi.num6); mulu();int output3()(intfor(k=l ;k<5;k+)(r=k;for(t=k+l ;t<=5;t+)if(p5.numr<p5.numt) r=t;if(r!=k)for(i=0;i<=5;i+) pi.num6=pi.numk;p i.numk=p i.num r;pi.numr=p i.num6;printf(1 fnnnnnrder of each good by total sum*nnn);printf(n g_num sum_monnn);fo

15、r(k= 1 ;k<=5 ;k+)printf(H %dtt%d rT',p0.numk,p5.numk);mulu();int output4()int i,k;int flage =0;printf(''ntte port forms of goods *nnnH);printR“g_num np_numt 1 t2t3t4t5tsumnn1');fbr(i=l ;i<=4;i+) for(k=0;k<=6;k+)printf("%dt",pi.numk);printf(AnnH);printf(Htotaltn);fb

16、r(k=l ;k<=6;k+)printf(H%dtH,p5 .numk);if(flage=O) save();flage = l;printf(nnnTheinformation has been saved successftilly!-(File:date.txt)H);) mulu();int save()(FILE 忡；int i,k;if(ip=fopen(',date.txtn,"w,)=NULL) (printf(,rnCan not open the file,please press any key to escape!");exit(l

17、);)fprintf(fp,ng_num rnp_numtlt2t3t4t5tsumrnu);fbr(i=l ;i<=4;i+) for(k=0 ;k<=6 ;k+)fprintf(fp,n%dtn,pi.numk);中 rinmijVArXn");)lprintf(ip,ntotal ”)；for(k=l ;k<=6;k+)fclose(tp);4）執(zhí)行結(jié)果of people*»THE PROJECT*0,exi tPlease Choose (0-4):|h m m . km； h m H0derp_niim凝 CAW i n do wsX sy st

18、 e m 3 2c mdt exeu回3n C:WindowssysternS2cmd.exeB回 Sn o m-02341,count the g_mon of each goods every people products last month2 .put the people in order by g_mon and output the result by p_num3 .count the total g_monfoutpui the result in order from high to low4 .output the report form of goods»*

19、0rderof each good by total sum*g_num- 12sum mon009 Li 0*«*THE PROJECT*1 .count the of each goods euery people products last month2 .put the people in order by g_«on and output the result by p_num3 .count the total g_mon.output the result in order From high to low put the report form of goodsPlease Choose (0-4):p_num12345sum1000000200000030000004Q00000total000000The informationhasbeen savedsuccessfully'(File:dale.txt)*the project*1 .count the g_wion of each goods every people products last month2 .put the people in order by g_mon and output the result