1、2022/8/20KylinsoftStatics-Problems-1次數(shù)章節(jié)題目一1(S)P23-1.1(l)(g)、P24-1.2(k)、P27-1.3(c)(e)二2(S)P58-2.3、P60-2.14、P61-2.20三2(S) P63-2.28 、 P63-2.30 、 P64-2.32 、P64-2.34四3(S)P85-3.2、P86-3.11 、 P87-3.18、P90-3.28(f)、P91-3.40、P92-3.43五4(S)P111-4.2 、P113-4.12、 P113-4.13 六4(S)P114-4.14(b)、P115-4.24 、P116-4.27七5(

2、S)P131-5.2、P132-5.12 、P133-5.18 、 P133-5.19 、 P134-5.22作業(yè)題目作業(yè)題目2022/8/20KylinsoftStatics-Problems-2P23-1.1(l):2022/8/20KylinsoftStatics-Problems-3P23-1.1(g):2022/8/20KylinsoftStatics-Problems-4P24-1.2(k):2022/8/20KylinsoftStatics-Problems-5P27-1.3(c):2022/8/20KylinsoftStatics-Problems-6P27-1.3(e):20

3、22/8/20KylinsoftStatics-Problems-7P58-2.3:Solution:由此得到如下方程組：解得：2022/8/20KylinsoftStatics-Problems-8P60-2.14:Solution:按定義有:So, expressions (a), (d), (e) are valid.2022/8/20KylinsoftStatics-Problems-9P61-2.20:Solution:(a)Vector form:2022/8/20KylinsoftStatics-Problems-10(b)Vector form:2022/8/20Kylinso

4、ftStatics-Problems-11P63-2.28:+Solution:2022/8/20KylinsoftStatics-Problems-12P63 -2.30:+（a)Solution:2022/8/20KylinsoftStatics-Problems-13(b)+2022/8/20KylinsoftStatics-Problems-14OOriginal forces and couple can be reduced to a force and a couple acting at point O:P64-2.32:Solution:于是得到合力的大小、方向和作用線位置（

5、如圖所示）：(或,或)2022/8/20KylinsoftStatics-Problems-15P64-2.34:+Solution:2022/8/20KylinsoftStatics-Problems-16P85-3.2:Solution:RAyRByFrom the FBD of the beam in Fig:+RBx3kN2m+2022/8/20KylinsoftStatics-Problems-17P86-3.11:Solution:GPGL把人和梯子作為研究對(duì)象，作出FBD(a) x=1.5m+RBRAyRAx+2022/8/20KylinsoftStatics-Problems-

6、18+GPGLRBRAyRAx(b) 2022/8/20KylinsoftStatics-Problems-19P87-3.18:Solution:300N0.5mRDRE(1) Studying entire structureFrom the FBD of entire structure in Fig:+(2) Studying member ABFrom the FBD of member AB in Fig:RBxRByRAxRAy300N0.5m1.6m+2022/8/20KylinsoftStatics-Problems-20(3) Studying member ACEFrom

7、 the FBD of member ACE in Fig:0.8mRERAxRAyAECRCxRCy0.8m0.6m0.6m+2022/8/20KylinsoftStatics-Problems-21P90-3.28(f):Solution:(1) Studying member CDFrom the FBD of member CD in Fig:顯然，本題中在約束A、B、C、D處沒(méi)有水平方向的作用力RCRMRCR2qC3m1m+2022/8/20KylinsoftStatics-Problems-22(2) Studying member ABCRARCRB2qAC1m2mRARCRB1

8、mFrom the FBD of member CD in Fig:+2022/8/20KylinsoftStatics-Problems-23P91-3.40:Solution:(1) From the FBD of joint A in Fig:APFABFAD12+2022/8/20KylinsoftStatics-Problems-24(2) From the FBD of joint B in Fig:BPFBCFBDFAB+2022/8/20KylinsoftStatics-Problems-25(3) From the FBD of joint D in Fig:DFBD+FDE

9、FADFCD1212122022/8/20KylinsoftStatics-Problems-26(4) From the FBD of joint C in Fig:CRCFCEFBCFCD12+2022/8/20KylinsoftStatics-Problems-27P92-3.43:Solution:(1) From the FBD of joint D in Fig:DPFCDFDH+(1) From the FBD of joint in Fig:HFDHFGFC2323+2022/8/20KylinsoftStatics-Problems-28P111-4. 2:Solution:

10、+2022/8/20KylinsoftStatics-Problems-29P113-4.12:Solution:RAzRAyRByRBxRCxRCzFrom the FBD of bent pipe and cable in Fig:2022/8/20KylinsoftStatics-Problems-30無(wú)解?。?022/8/20KylinsoftStatics-Problems-31P113-4.13:Solution:2022/8/20KylinsoftStatics-Problems-32P114-4.14(b):Solution:S令形心坐標(biāo)為(xc, yc), 按定義有:2022

11、/8/20KylinsoftStatics-Problems-33P115-4.24:Solution:已知crucible的密度rc=2000kg/m3, 外徑R=0.28m, 內(nèi)徑r=0.2m; iron的密度ri=7200kg/m3OStudying crucible，Drawing FBD in Fig.WiWcGiGcFyFx+2022/8/20KylinsoftStatics-Problems-34OWiWcGiGcFyFx2022/8/20KylinsoftStatics-Problems-35P116-4.27:Solution:x=0 2022/8/20KylinsoftSt

12、atics-Problems-36xyO2xyO1P131-5.2:解：3036lb20lb18in假設(shè)系統(tǒng)是靜力平衡的先研究圓柱，有P1G1G2N1N2f2f1P1得再研究方塊，有得而因，所以系統(tǒng)不能保持靜力平衡2022/8/20KylinsoftStatics-Problems-37P132-5.10:Solution:總體分析: 分析木條 :圓盤(pán)分析 :解之得： NfffCBA.=22.06=達(dá)到最大靜摩擦力時(shí) :解之得： 2022/8/20KylinsoftStatics-Problems-389000N/mBCDBCDP132-5.12:解：P假設(shè)系統(tǒng)是靜力平衡的先研究樁子CBD，有NBNBNAfAfBRxRy再研究桿AB，有P9000N/m1.5m2m3m0.8mABCDABfBAB2022/8/20KylinsoftStatics-Problems-39只有當(dāng)fAfAmax或fBfBmax時(shí)，桿AB才能移動(dòng)，由以上計(jì)算結(jié)果可知，當(dāng)P6300(N)，桿AB在A點(diǎn)處開(kāi)始移動(dòng)2022/8/20Ky