經(jīng)典word整理文檔，僅參考，雙擊此處可刪除頁眉頁腳。本資料屬于網(wǎng)絡(luò)整理，如有侵權(quán)，請聯(lián)系刪除，謝謝！(a)(ⅠⅡ)(ⅠⅢ)Ⅰ`Ⅱ(ⅡⅢ)Ⅲ(b)(c)(d)(b)（ⅠⅡ）Ⅰ（ⅠⅢ）Ⅲ2-4試分析圖示體系的幾何構(gòu)造。ⅠⅡ（ⅡⅢ）（ⅠⅡ）（ⅠⅢ）Ⅲ(b)(c)ⅠⅡⅢ(d)ⅡⅠⅢ(e)ⅢⅠⅡ（ⅠⅢ）（ⅡⅢ）(f)ⅢⅠⅡ(g)（ⅠⅢ）（ⅡⅢ）（ⅠⅡ）ⅠⅡⅢ(h)多余約束（ⅠⅢ）W=3×8-9×2–7=-1,有1個多余約束二元體(a)ⅡⅠⅢ(b)幾何不變ⅡⅠⅢ同濟大學(xué)朱慈勉結(jié)構(gòu)力學(xué)第3章習(xí)題答案3-2試作圖示多跨靜定梁的彎矩圖和剪力圖。(a)PAFBCDEaaaaaFFP2P43FP4(b)2kN/mABDC2m2m6m4mMQ４４20kN/m4mABDFCE2m2m3m3m3mMQ40(d)ADFGHBCE2m2m2m2m2m2mA84542.53-3試作圖示剛架的內(nèi)力圖。2kNmm6/Nk13mMQ6(b)BACm3Dm36mMQ2kN/mBm36kNm3A6mMQ564762(d)·DmEm2AB6mQ42444N00Cm/Nmk41ABD4m44``841(f)CBm4A3m2m4mMQ15N3-4試找出下列各彎矩圖形的錯誤之處，并加以改正。(b)(c)FP(d)M(f)FPFPqADEBCxlll8MADEBCFq12222FDcM中BC1M2qC21x22183-6試作圖示剛架的彎矩和剪力圖。90M9045對B點求矩209(4.53)R6R)135405FFM0.5209459405,R135()2EEQCFCDM0.520990BA(b)11M3.75Q12.12.95.754.25EM2KBB2422H4H)BBVH)AAQ24K左EF160QM80/33016016408080160808033C對F點求矩:V(2023304)/2120()C對點求矩:V61201030420211B3203B803A(d)4MQ16/344/3204/38/388M414233:416142V8V4()BB43BB83AAMQFFFF----2Fa2Fa+2Fa2Fa2FaM0V2F(),M02HVCBEBFBPHPFHPFPDPD(f)844488++--44+-4488-+8488HIVIHB88VBBBIIA(g)qGIJFHHaH1.5qa()22CC對F點求矩：BCaaaaaAAH0,Mqa,M1.5qa22DGFGH22qa222qa2qa222PDEaBAaaaaF0,RRFFF2FFFFFFABPNBEPPDEP122222211221211222PPNPPN262PPP5FPPk54PPF5FF2FNADPNAEP554NECPNEF1k521(12F251F6(-5)(5F)254)5NP42PPP5-5已知桁架各桿的EA相同，求AB、BC兩桿之間的相對轉(zhuǎn)角Δ。44884444142124814111442411NB5-6）Δb）Δ）d）Δ。yByCBxB(a)AB2l11222lp1111ll(qx234lp1001q11=(2120(b)qBClEI=常數(shù)Alq2lq47l4MMP11ql2(lEI33153251q31512722242443422434(c)1kN/m2kNBR=2m4mAO1M)(Rsin)12R(1cos)22M)1111[(Rsin)12R(1cos)]Rd22B0(8-3)-1.42=(逆時針)EIEI(d)AqREI=常數(shù)OB20M)Rsin1112qR(1cos)RsinRd24EIEIxB0）Δ。yCyDxED(a)1以為原點，向右為正方向建立坐標(biāo)x(0x3)13x(3x6)181EI0(b)2kN/mEABDC常數(shù)6m0.5PA1366116236yD6EI8311(32162(3)(6))225+1BCm6/NmEIEIk621DA421863630MMPxc918+EI38EI(e)2kN/m4kNCDkm6ABEIk13.5MMP18421226MMDk6EIP1412xBCD（）CDlABl1LL11MN12221tFdsNhkt0101301l22h2ll(102l)/l210(b)11CD3m43A0B00tt1114m4m4mN圖t5t5Nh4kt05tt5(1)(432442h23M圖354.5t()5-10）Δb）yCCCCEDE′′CΔChABB′ba111hh001aFC[()a](方向與圖示一致)Rhh1ABCDc1c3A′c2B′′′00.51.5F圖aR13C]CC()R2yc12213515311[CCCC2233512(d)I(e)9I(f)(g)所有結(jié)點均為全鉸結(jié)點II4次I(h)QABClFp+l1MM1pX012lll333112l2233p33ppl33X0p1121pp16pp11p12pp(b)DABECFllM1l3lM2FlpFPMp1Fl3pXX0111221121212p1122p20kN/mCDEIm66m3m解：基本結(jié)構(gòu)為：20kN/m61M16MpX01MMXMp(b)Ea2a4AM計算，由對稱性知，可考慮半結(jié)構(gòu)。11122M1Mpqa2q2qa22qaqa22qqa2qa2214qa2MpX011p11p6-5試用力法計算圖示結(jié)構(gòu)，并繪出M圖。(a)Cm611kNDm63m3m111KN61126MM12p,011112202112222p(b)EI=常數(shù)m620kN/m6mB6m解：基本結(jié)構(gòu)為：20kN/m63633MM12MMp6108EI661086EIEI1122131227002EI2338223EI11221312540618036206618032338223X0X11X5X021M18032553120KNmM6530KNm(c)CDI310kNm·m6AB12m113310kNm·99NMM11p66X0X1.2911M36.13mDAM31.293.87KNmDCM(d)DEIIm3mFG/Nm6ABCm/N11339966MM1236111.6116EIEI625.26650.4266EI361241721.25XX012125.250.4X8.69XX0212M68.69917.39104.37mM68.6952.14KNmCG52.17M248.49104.3752.1411ma25.12FPFPaaa2m2m題6-6圖(a)ABEIk=lEA=llCllFlFpPMM1plllkFll3ppk2EIpp2X0XF711p23MFlFlFl77Appp3Fl7pFlMp(b)qqaEFGCAaa(a)DAmEI9B6m6mFFFFpppp222+2Fp2F1pp2299MM1p21211231192F223pp1X0XF41111pFFFppFFpppM圖(b)60kNCDm3AB4m4m(c)qEI=常數(shù)lq基本結(jié)構(gòu)為：qqX1181MM1p1ll2lql222EI32812EI2X0X11p111p22222222M(d)qDEFEI=常數(shù)lABCqll基本結(jié)構(gòu)為：ql22l1MMM12p231111l22l2223242422lql5324XX0Xql121211llql32XqlXX2212229922222M29FmI6CIm6AB9m(f)HGIa2DAa2(BEH桿彎曲剛度為2EI，其余各桿為EI)aaaaFFFFppppp=+FFFF2FpppppFFFpppp222=+FFFFFppFpp2pp2FFFpp2FapF2p2彎矩圖如下：FFapap22FFap2FFap22FFap22Fap2(g)kFFPCAGDBEI=常數(shù)aa+FFFFpppp2222Fp2基本結(jié)構(gòu)為：X1Fp21Fp2F2a2MM1p1122a2a2a2FFa3ppp6EI22XXp111p111pM圖如下：5577(h)DFIIIIIIhACEllllABCDEEI=常數(shù)2llCDa3ABB′題6-10圖6-11試?yán)L出圖示結(jié)構(gòu)因溫度變化產(chǎn)生的M圖。已知各桿截面為矩形，EI=常數(shù)，截面高度h=l/10，材料線膨脹系數(shù)為。(a)(b)-15℃+15℃CABB-15℃+25℃ll+15℃CDA+5℃lllFPABCDABl6-14試求題6-11a所示結(jié)構(gòu)鉸B處兩截面間的相對轉(zhuǎn)角Δ。B6-15試判斷下列超靜定結(jié)構(gòu)的彎矩圖形是否正確，并說明理由。(c)qqCRABRR7-1試確定圖示結(jié)構(gòu)的位移法基本未知量數(shù)目，并繪出基本結(jié)構(gòu)。EIEIEI2EI2EI13111EIEA31個線位移2個線位移32個線位移k一個角位移，一個線位移三個角位移，一個線位移以將靜定部分的結(jié)點位移也選作位移法未知量？7-3試說出位移法方程的物理意義，并說明位移法中是如何運用變形協(xié)調(diào)條件的。(a)qAiDCilBlr1Riiip1rZR01123111231ql2Zi175M(b)2.5kN/mADEIm44m4m1）確定基本未知量1個角位移未知量，各彎矩圖如下Z1rEI1EI2p152111Z7MmEI9B6m6m1）確定基本未知量一個線位移未知量，各種M圖如下Z1rRFpEI227MM圖121p14243p42431pZ9F(d)EFEAEAa2ABCDEI∞1aarZ1125rM圖1R43aaFp5圖Mp126rEA/a,RF55p1paZpppCEAl1r112EAl42EAllrZ12222EA22l4lM200p0M111122rZrZR02112222p2l4l2l4pl1lZ2Fp21pM10kN/mFACEmEI=常數(shù)6BD6m6m6m1r3131EIEI631EI321pM圖prZrZR01212131112211162212M(b)ABm6EI=常數(shù)10kN/mCDE6m6mi/2riiiM圖2RM1212r11i,rr0111221i4R30KN,R30KN3011i12圖M(c)Cm230kNAEBDFEI=常數(shù)m22m2m2m兩個位移未知量，各種M圖如下i113iM圖1ii22M圖230KNM圖prZrZR01111222112223）確定系數(shù)并解方程ir11i,rr2111221i4EIEI2M圖(d)EqqlGFEI=常數(shù)ll兩個位移未知量，各種M圖如下l1r4EIllll1l22Z1l2l2l2218ql212qlRRp12123）確定系數(shù)并解方程ll2l21Rql,Rql216342圖(e)20kNDABC4m4m3421EIEI1r1EI22rEIM圖2p12123）確定系數(shù)并解方程51411122182212M圖7-7試分析以下結(jié)構(gòu)內(nèi)力的特點，并說明原因。若考慮桿件的軸向變形，結(jié)構(gòu)內(nèi)力有何變化？(a)(b)(c)(d)(e)(f)MqEI∞EI7-8試計算圖示具有牽連位移關(guān)系的結(jié)構(gòu)，并繪出M圖。對稱軸(a)20kNEBEI∞1m3G1EIm6ACF8m8m圖1）畫出M,M,M12pZ1431443EI81r0212EI91124813r14Z1EIEI63EIEI113EIEI621EI12EI2EI96M圖214rEI229R2pp1pR02p412491211EIEI12M圖(b)Dm6BCm410kN10kNm4EI=常數(shù)A8m3解：C點繞D點轉(zhuǎn)動，由Cy=1知，x4知9EI3EI3EIrEI,rr,rr1113128323128327221081023323240160R10KNm,RR6.25KNr求D273399EI1440r338EI3Z143EI1ZZ411021602732Z285.6/EI33EIZZ0.055EIZ6.25012823B1EIEIaAa2a2aa2a2a2a2a2a2M圖1a3a3011ra311PR1Pa4M圖pa202111Pa35M圖(d)qEI∞1ABCEIDk=l3l2ll2解：基本結(jié)構(gòu)選取如圖所示。作出M及M圖如下。1pll22Z1lrM圖128M圖plllll32222117R/l224115768128M圖BAAC(b)BByB′AC7-10試計算圖示有剪力靜定桿的剛架，并繪出M圖。qqaGFCBqEDAaa12pr1811ql2ii1282qlql2iql2M圖M圖M圖1p2由圖可知，得到各系數(shù)：r7i,rri,ri111221513Rqa,Rqa21p288求解得：Z122104244022ql220kN/mAECmEI常數(shù)66m6m6m6mEIZ1rREIM圖p4343131M圖(b)CEIEIm3