單片機(jī)實驗報告（自動化15級）實驗名稱:串行通訊實驗一、實驗?zāi)康?．掌握單片機(jī)串行口工作方式；2．掌握雙機(jī)通訊的接口電路設(shè)計及程序設(shè)計。二、實驗設(shè)備1.PC機(jī)；2．單片機(jī)最小系統(tǒng)教學(xué)實驗?zāi)K；3.數(shù)碼管顯示模塊三、實驗內(nèi)容1．雙機(jī)通信由兩套單片機(jī)試驗裝置（兩個實驗小組）共同完成該實驗。我們U1為甲機(jī)，U2為乙機(jī)。甲機(jī)發(fā)送本機(jī)（學(xué)生本人）學(xué)號后8位給乙機(jī)，乙機(jī)接收該8位數(shù)據(jù)，并顯示在8位數(shù)碼管上。電路如圖1所示。要求串行通信方式為方式1，波特率為2400bit/s,不加倍，單片機(jī)外部晶振頻率為11.0592M。圖1雙機(jī)通信原理示意圖ucharxuehao[8]={6,6,6,6,6,6,6};voidmain(void){ init(); send(); while(1); }voidinit(void){ TMOD=0x20; TH1=0xfd; TL1=0xfd; SCON=0x50; PCON=0x00; TR1=1;}voidsend(void){ uchari; do { delay(200); SBUF=0xaa; while(TI==0);TI=0; while(RI==0);RI=0; }while(SBUF!=0xbb); //----------------------------------????? delay(80); for(i=0;i<=7;i++) { SBUF=xuehao[i]; while(TI==0);TI=0; delay(5); } SBUF=9; delay(10); }///////////////////////////////////////////////////////////voiddelay(unsignedinti){ unsignedcharj; for(;i>0;i--) for(j=0;j<125;j++) {;}}#include<STC12C5A60S2.h>#defineucharunsignedcharvoidinit(void);voidreceive(void);voiddelay(unsignedinti);voiddisplay(ucharA,ucharB);voidduanxuan(ucharc);ucharxuehao[8]={0};voidmain(void){ init(); receive(); while(1) { display(1,xuehao[0]); delay(3); P0=0x00; display(2,xuehao[1]); delay(3); P0=0x00;display(3,xuehao[2]); delay(3); P0=0x00; display(4,xuehao[3]); delay(3); P0=0x00; display(5,xuehao[4]); delay(3); P0=0x00; display(6,xuehao[5]); delay(3); P0=0x00;display(7,xuehao[6]); delay(3); P0=0x00; display(8,xuehao[7]); delay(3); P0=0x00; } //}voidinit(void){ P0M1=0X00; P0M0=0Xff; P2M1=0x00; P2M0=0xff; TMOD=0x20; TH1=0xfd; TL1=0xfd; SCON=0x50; PCON=0x00; TR1=1;}voidreceive(void){ ucharenpty; ucharj=0; do { while(RI==0);RI=0; }while(SBUF!=0xaa); SBUF=0xbb; while(TI==0);TI=0; enpty=SBUF;// while(RI==0);RI=0; //-------------------------------?? delay(10); for(j=0;j<=7;j++) { xuehao[j]=SBUF; while(RI==0);RI=0; }}////////////////////////////////////////????//////////////////////////////////////////////////voiddisplay(ucharA,ucharB){ ucharcodeinfo[12]={0xc0,0xf9,0xa4,0xb0,0x99,0x92,0x82,0xf8,0x80,0x90, // 0xff, 0xbf};//- duanxuan(A); switch(B) { case0: P0=~info[0]; break; case1: P0=~info[1]; break; case2: P0=~info[2]; break; case3: P0=~info[3]; break; case4: P0=~info[4]; break; case5: P0=~info[5]; break; case6: P0=~info[6]; break; case7: P0=~info[7]; break; case8: P0=~info[8]; break; case9: P0=~info[9]; break; case10: P0=~info[10]; break; case11: P0=~info[11]; break; }}voidduanxuan(ucharc){ switch(c) { case1: P2=0x01; break; case2: P2=0x02; break; case3: P2=0x04; break; case4: P2=0x08; break; case5: P2=0x10; break; case6: P2=0x20; break; case7: P2=0x40; break; case8: P2=0x80; break; default: break; }}////////////////////////////////////////////////////////////////////////////