課程設計設計題目測量顯微鏡學生女學_號專業(yè)班級指導教師光學顯微鏡設計根據學號得到自己設計內容的數據要求：目鏡放大率10（即焦距25）目鏡最后一面到物面距離110對準精度1.2微米按照實驗步驟，先計算好外形尺寸。然后根據數據要求選取目鏡與物鏡。我先做物鏡。因為這個鏡片比較少。按物鏡放大率選好物鏡后，將參數輸入。簡單優(yōu)化，得到比較接近自己要求的物鏡。然后做目鏡，同樣的做法，這個按照焦距選目鏡，將參數輸入。將曲率半徑設為可變量，調入默認的優(yōu)化函數進行優(yōu)化。發(fā)現“優(yōu)化不了”，所有參數均沒有變化。而且發(fā)現把光源放在“焦點”位置，目鏡出射的不是平行光。我百思不得其解。開始認為鏡頭庫的參數可能有問題。最后我問老師，老師解釋，那個所謂的“焦點”其實不是焦點，我錯誤的把“焦點”到目鏡第一個面的距離當成了焦距。這個目鏡是有一定厚度的，不能簡單等效成薄透鏡。焦點到節(jié)點的距離才是焦距。經過老師指點后，我嘗試調節(jié)光源到目鏡第一面的距離，想得到出射平行光，從而找到焦點。但這個尋找是很費力氣的，事倍功半。老師建議我把目鏡的參數倒著順序輸入參數。然后用平行光入射，然后可以輕松找到焦點。但是，按照這個方法，倒著輸入參數，把光源放在無限遠的地方（平行光入射），發(fā)現光線是發(fā)散的。不解。還是按照原來的方法。把光源放在目鏡焦點上，盡量使之出射平行光。然后把它與優(yōu)化好的物鏡拼接起來。后來，加入理想透鏡（會聚平行光線），加以優(yōu)化。還有一個問題，就是選物鏡的時候，發(fā)現放大倍率符合了自己的需求，但工作距離與共軛距，不符合自己的要求。這個問題在課堂上問過老師，后來經老師指點，通過總體縮放解決。哉中隕■邪Mh￡d^lE>R壬FE白分始心^:■■少I*TTPhi|T.事有伉mW網湖5伊WWg呵e|w「Lwggj|n*l*|l*|「呻|ukWf<|舊|抽[口以土l?|]知|■At;■-21處做E402柔"dgUhTf『MT^p*rtgT^ngwr4?L3iEbJL3HF9.3ILHuu?3，頌W4Tcafaul^ibicasfjijE：Eiccalr^i.415DU4Pcufuilrihie'vMi^uxdirrccEicrMdr^v.,fi1^1EKJVseai.I=CM=cm3Ei.EfiUCSs3.-??133331133C.ECACrMs!9.O??3E心!《H-■uMMU~ML4.JMII&7ma:ccw&.rww<fl.w?'，?E1O.MWW12131]1J.9LHI239FNMWJo.cwwS.ci.a-mu1.MH44-#.MWWilCCCai￡>.￡4juu?4.<KuM^3“51姑Cf.uUuM■上m”-U.LKifiUM.以“心L-3?=4ZCDKE-.MCMC-3.-H434337I13I14.O3O3MC333133=■.3?TE-CZ-->?LL=fWs.cwwciD.WWW■J.TO1-M!"$M?WL4MLAL■iflF：.?-,3.-E-rK：m^PPFMI>?P：!Sace-ZTHMl>jb?*t匕Um》1Li.liLRO4liLhilL=,；■SSaiRdiE^-LI992313W.IPM-MLMKWLInine!TC-SsiEiiEiK”LlJ凹4%MLI*4.MHMKIE3.iidilCiKJi■itiiiCiEFn_UJM77VWNQLZIHiEWQZUl^TOIItU3L1]物鏡參數及優(yōu)化函數

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