版權(quán)說明:本文檔由用戶提供并上傳,收益歸屬內(nèi)容提供方,若內(nèi)容存在侵權(quán),請(qǐng)進(jìn)行舉報(bào)或認(rèn)領(lǐng)
文檔簡(jiǎn)介
期末作業(yè)匯報(bào)一、兩獨(dú)立樣本:1、獨(dú)立性:滿足2、方差齊性檢驗(yàn):?sdtesty,by(group)VarianceratiotestGroup|LObsMeanStd.Err.Std.Dev.[95%Conf.Interval]十0129.0225572.56525783.044006—1?1353211.1804351|L162.415993?76094263.04377.79408214.037904十combined|45.8735565?48067863.22449—.09518761.842301Ho:sd(0)=sd(1)TOC\o"1-5"\h\zF(28,15)observed=F_obs=1.000F(28,15)lowertail=F_L=1/F_obs=1.000F(28,15)uppertail=FU=Fobs=1.000Ha:sd(0)<sd(1)Ha:sd(0)~=sd(1)Ha:sd(0)>sd(1)P<F_obs=0.4818P<F_L+P>F_U=0.9997P>F_obs=0.5182
由軟件結(jié)果可知,P=0.9997>0.10,不能拒絕H/故可以認(rèn)為方差齊性。3、正態(tài)性檢驗(yàn):.sktestyifgroup==0Skewness/KurtosistestsforNormalityjointVariable|Pr(Skewness)Pr(Kurtosis)adjchi2(2)Prob>chi21y|0.4530.8170.650.7241?sktestyifgroup==1joint
Variable|Pr(Skewness)Pr(Kurtosis)adjchi2(2)Prob>chi2+y10.0760.3974.150.1257由軟件結(jié)果可知,兩組的P值都大于0?05,故不能拒絕H0,可認(rèn)為兩組資料服從正態(tài)分布。4、t檢驗(yàn):由于資料滿足獨(dú)立性、方差齊性和正態(tài)性三個(gè)條件,故選擇t檢驗(yàn)。ttesty,by(group)Two-samplettestwithequalvariancesGroup|LObsMeanStd.Err.Std.Dev.[95%Conf.Interval]十0129.0225572.56525783.044006-1?1353211.1804351|L162.415993?76094263.04377?79408214.037904十combined|L45.8735565?48067863.22449-.09518761.842301十diff|-2.393436?9479405—4.30514-.4817315Degreesoffreedom:43Ho:mean(0)-mean(1)=diff=0Ha:diff<0Ha:diff~=0Ha:diff>0t=一2.5249t=一2.5249t=一2?5249P<t=0.0077P>|t|=0.0153P>t=0.9923由軟件結(jié)果可知,P=0.0153<0.05,拒絕H0,接受H1,即兩種藥物治療慢性腎炎的療效不同;由于0組的樣本均數(shù)(0?0225572)小于1組的樣本均數(shù)(2.415993),故可推斷B藥的效果更好。5、秩和檢驗(yàn):?ranksumy,by(group)Two-sampleWilcoxonrank-sum(Mann-Whitney)testgroup|obsranksumexpectedT-01295556671|L16480368十combined|45103510351778.670.001778.670.00adjustedvarianceadjustedvariance1778.67Ho:y(group==0)=y(group==1)z=一2?656Prob>|z|=0.0079二、三個(gè)獨(dú)立樣本:1、獨(dú)立性:滿足2、方差齊性檢驗(yàn):ygroup;predicte,residual;genee=abs(e);onewayeegroup:onewayeegroupSourceSSdfMSFProb>FBetweengroups.0322453732.0161226870.030.9690Withingroups30.224460959.512278998Total30.256706261.496011578Bartlett'stestforequalvariances:chi2(2)=0.9884Prob>chi2=0.610由軟件結(jié)果可知,P>0.10,方差齊性,下面進(jìn)行正態(tài)性檢驗(yàn)。3、正態(tài)性檢驗(yàn):swilkyifgroup==1VariableShapiro-WilkWtestfornormaldata|ObsLWVzProb>zy十|220.925081.8981.2990.09691swilkyifgroup==2Variable|ObsWVzProb>zy11170.964780.744-0.5890.72222swilkyifgroup==3Variable|ObsWVzProb>zchi-squaredwithties=chi-squaredwithties=33.000with1d.f.y|230.899432.6311.9670.02460由軟件結(jié)果可知,第3組不滿足正態(tài)性的要求,故選用K-W檢驗(yàn)。4、K-W檢驗(yàn):chi-squared=probability=?kwallisy,by(group)chi-squared=probability=Test:Equalityofpopulations(Kruskal-Wallistest)group_Obs_RankSum122276.00217506.003231171.0051.070with2d.f.0.0001chi-squaredwithties=51.070bability=0.0001由軟件結(jié)果可知,P<0?05,故三種藥治療慢性腎炎的有效率不全相同。5、兩兩比較:采用Bonferroni法,校正后的a=0?05/3=0.01667chi-squared=probability=kwallisyifgroup==1|group==2,by(group)chi-squared=probability=Test:Equalityofpopulations(Kruskal-Wallistest)group_Obs_RankSum122276.00217504.0021.574with1d.f.0.0001hi-squaredwithties=21.574with1d.f.robability=0.0001ifgroup==1group==3,by(group)ifgroup==1group==3,by(group)group_Obs_RankSumgroup_Obs_RankSum22253.00323782.00chi-squared=probability=33.000with1d.f.0.0001probability=0.0001ifgroup==2probability=0.0001ifgroup==2group==3,by(group)group_0bs_RankSum17155.00chi-squared=probability=23665.00chi-squared=probability=28.027with1d.f.0.0001chi-squaredwithties=28.027bability=0.0001由于每?jī)山M之間比較的P值都小于a,故可推斷三種藥治療慢性腎炎的有效率都不相同。6、方差分析:?onewayygroupSourceAnalysisofVarianceSSdfMSFProb>FBetweengroups383.7919092191.895955148.750.0000Withingroups76.1134674591.29005877Total459.905377617?5394324Bartlett'stestforequalvariances:chi2(2)=0.3200Prob>chi2=0.8527、兩兩比較:?lsdygroupLSD方法進(jìn)行兩兩均數(shù)比較
輸入效應(yīng)變量分組變量
mean1-mean2=-2.742864P-value=0.000000mean1-mean3=一5?836804P-value=0.000000mean2-mean3=-3.093940P-value=0.000000?onewayygroup,bSourceAnalysisofVarianceSSdfMSFProb>FBetweengroups383.7919092191.895955148.750.0000Withingroups76.1134674591.29005877Total459.905377617?5394324Bartlett'stestforequalvariances:chi2(2)=0.3200Prob>chi2=0.852Comparisonofybygroup(Bonferroni)RowMean-|ColMean|412+2|112.742860.0003|15.83680.0003.093940.000三、'配對(duì)資料1、獨(dú)立性:數(shù)據(jù)獨(dú)立,先考慮配對(duì)t檢驗(yàn)2、正態(tài)性檢驗(yàn):gend=x1-x2swilkdShapiro-WilkWtestfornormaldataVariable|ObsWVzProb>z+d|320.983270.558-1?2110.88707由軟件結(jié)果可知,差值服從正態(tài)分布,選用配對(duì)t檢驗(yàn)。3、配對(duì)t檢驗(yàn):ttestd=0Variable|ObsMeanStd.Err.Std.Dev.[95%Conf.Interval]L十d|32-.3875.75401814.265371-1.925331.15033Degreesoffreedom:31Ho:mean(d)=0Ha:mean<0Ha:mean~=0Ha:mean>0
t=—0.5139t=—0.5139t=—0.5139P<t=0.3055P>|t|=0.6110P>t=0.6945由軟件結(jié)果可知,P值>0?05,不能拒絕H0,故不能認(rèn)為這2種藥物治療高血脂的療效不同。4、符號(hào)秩和檢驗(yàn):?signrankxl=x2Wilcoxonsigned-ranktestsign|obssumranksexpected+一positive|14236263?5negative|17291263.5zero|L111十a(chǎn)ll|32528528unadjustedvariance2860.00adjustmentforties—0.88adjustmentforzeros—0.25adjustedvariance2858.88Ho:x1=x2z=-0.514Prob>|z|=0.6070本題可直接采用秩和檢驗(yàn):ranksumy,by(group)group|obsranksumexpected十0I40138913601I27889918十combined|6722782278unadjustedvariance6120.00adjustmentforties—2070.00adjustedvariance4050.00Ho:y(group==0)=y(group==1)z=0.456Prob>|z|=0.6486
由軟件結(jié)果可知,P值>0.05,故不能認(rèn)為兩種藥物的療效有差別。五、本題可直接采用符號(hào)秩和檢驗(yàn):?signrankyl=y2sign|Lobssumranksexpected十positive|7689.51576negative|252462.51576zero|L8234033403十a(chǎn)ll|11465556555unadjustedvariance125091.25adjustmentforties-682.00adjustmentforzeros-46791.25adjustedvariance77618.00Ho:y1=y2z=—3.182Prob>|z|=0.0015由軟件結(jié)果可知,P值<0.05,故兩種藥物的療效不同。六、隨機(jī)區(qū)組1、數(shù)據(jù)轉(zhuǎn)換:stackx1blockx2blockx3block,into(yblock)2、方差齊性檢驗(yàn):anovaygroupblock;predicte,residual;genee=abs(e);anovaeegroupblock:?anovaeegroupblockNumberofobs=99R—squared=0.4773RootMSE=1.04435AdjR—squared=0.1996Total|133.547507981.36272967由軟件結(jié)果可知,P<0.05,故方差不齊,采用Friedman檢驗(yàn)。3、Friedman檢驗(yàn):friedmanblb2b3b4b5b6b7b8b9bl0bllbl2bl3bl4bl5bl6bl7bl8bl9b20b21b22b23b24b25b26b27b28b29b30b31b32b33Friedman=23.8636Kendall=0.3616p-value=0.0000由軟件結(jié)果可知,P<0.05,故這3種藥物治療該疾病的療效不同。4、方差分析:?anovaygroupblockNumberofobs=99R-squared=0.6244RootMSE=2.31064AdjR-squared=0.4248Source|LPartialSSdfMSFProb>F十Model|567.9478983416.70434993?130.0000group|171.420602285.710301116.050.0000block|396.5272953212.3914782.320.00211Residual|L341.699399645.33905311十Total|909.647296989.28211527七、相關(guān)性檢驗(yàn):?pwcorrxy,sig1Lxy十x|||1.0000y10.66341.000010.0000由軟件結(jié)果可知,r=0.6634,P=0?0000<0.05,故pH0,因此,兩個(gè)指標(biāo)之間存在相關(guān)性。八、回歸分析:
?regyxSource|SSdfMSNumberofobs=17(1aa\—46十F(1,44)—?Model|93832.6765193832.6765Prob>F—0.0000Residual|28.477749344?647221576R-squared—0.9997AQQQ7十Adjrsquared—0.9997Total|93861.1542452085.80343RootMSE—.8045y|Coef?Std.Err.tP>|t|[95%Conf.Interval]+x|4.961854.0130315380.760.0004.935594.988117_cons|2.488645.226470910.990?0002.0322222.945067由軟件結(jié)果可知,y=2.49+4.96x。P值小于0.05,故該回歸方程成立。九、本題釆用Logrank檢驗(yàn):?ststestgroupfailure_d:deadanalysistime_t:timeLog-ranktestforequalityofsurvivorfunctions|EventsEventsgroup|observedexpected10|3120.27
111727.731Total|4848.00chi2(1)=10.84Pr>chi2=0.0010由軟件結(jié)果可知,兩種藥物的療效不同。十、樣本率與已知總體率的比較:?prtesti5060.15,countOne-sampletestofproportionx:Numberofobs=50Variable|LMeanStd.Err.zP>|z|[95%Conf.Interval]十X1.12?04595652.611160.0090.0299269.2100731Ho:proportion(x)=
溫馨提示
- 1. 本站所有資源如無特殊說明,都需要本地電腦安裝OFFICE2007和PDF閱讀器。圖紙軟件為CAD,CAXA,PROE,UG,SolidWorks等.壓縮文件請(qǐng)下載最新的WinRAR軟件解壓。
- 2. 本站的文檔不包含任何第三方提供的附件圖紙等,如果需要附件,請(qǐng)聯(lián)系上傳者。文件的所有權(quán)益歸上傳用戶所有。
- 3. 本站RAR壓縮包中若帶圖紙,網(wǎng)頁內(nèi)容里面會(huì)有圖紙預(yù)覽,若沒有圖紙預(yù)覽就沒有圖紙。
- 4. 未經(jīng)權(quán)益所有人同意不得將文件中的內(nèi)容挪作商業(yè)或盈利用途。
- 5. 人人文庫網(wǎng)僅提供信息存儲(chǔ)空間,僅對(duì)用戶上傳內(nèi)容的表現(xiàn)方式做保護(hù)處理,對(duì)用戶上傳分享的文檔內(nèi)容本身不做任何修改或編輯,并不能對(duì)任何下載內(nèi)容負(fù)責(zé)。
- 6. 下載文件中如有侵權(quán)或不適當(dāng)內(nèi)容,請(qǐng)與我們聯(lián)系,我們立即糾正。
- 7. 本站不保證下載資源的準(zhǔn)確性、安全性和完整性, 同時(shí)也不承擔(dān)用戶因使用這些下載資源對(duì)自己和他人造成任何形式的傷害或損失。
最新文檔
- CCAA - 2016年09月建筑施工領(lǐng)域?qū)I(yè)答案及解析 - 詳解版(70題)
- 民營(yíng)企業(yè)文化建設(shè)的思考
- 養(yǎng)老院信息化管理與服務(wù)制度
- 養(yǎng)老院服務(wù)質(zhì)量監(jiān)督制度
- 再生塑料顆粒生產(chǎn)建設(shè)項(xiàng)目環(huán)評(píng)報(bào)告
- 老年終末期跌倒預(yù)防的循證護(hù)理方案
- 央國企動(dòng)態(tài)系列報(bào)告之56:地方國資會(huì)議定調(diào)改革深化多元布局培育新質(zhì)生產(chǎn)力-
- 老年終末期壓瘡疼痛的評(píng)估與護(hù)理策略
- 我國上市公司現(xiàn)金持有量與企業(yè)績(jī)效關(guān)系的深度剖析:基于多維度視角與實(shí)證研究
- 我國上市公司控股股東掏空性并購的多維度影響因素剖析與治理路徑
- 2026年安徽皖信人力資源管理有限公司公開招聘宣城市涇縣某電力外委工作人員筆試備考試題及答案解析
- 2026中國煙草總公司鄭州煙草研究院高校畢業(yè)生招聘19人備考題庫(河南)及1套完整答案詳解
- 骨科患者石膏固定護(hù)理
- 陶瓷工藝品彩繪師崗前工作標(biāo)準(zhǔn)化考核試卷含答案
- 居間合同2026年工作協(xié)議
- 醫(yī)療機(jī)構(gòu)信息安全建設(shè)與風(fēng)險(xiǎn)評(píng)估方案
- 化工設(shè)備培訓(xùn)課件教學(xué)
- 供熱運(yùn)行與安全知識(shí)課件
- TOC戰(zhàn)略思想《關(guān)鍵鏈》
- GB/T 39239-2020無損檢測(cè)超聲檢測(cè)不連續(xù)的特征和定量
- GB/T 34843-20173.3硼硅玻璃性能
評(píng)論
0/150
提交評(píng)論