1、1要求：使用兩個數(shù)碼管，并從01開始，每隔1s數(shù)碼管加1，一直顯示到60.C語言：#include #define uchar unsigned char#define uint unsigned int sbit dula=P26; /段選，申明鎖存器1的鎖存端 sbit wela=P27; /位選，申明鎖存器2的鎖存端 uchar code table= /共陰極數(shù)碼管編碼 0x3f,0x06,0x5b,0x4f, 0x66,0x6d,0x7d,0x07, 0x7f,0x6f ;void delayms(uint xms) /延時xms uint i,j; for(i=xms;i0;i-)

2、 for(j=110;j0;j-);void display(uchar,uchar);uchar num,num1=1,shi,ge=1; /賦初值void main()TMOD=0x10; /設(shè)定時器1方式1定時50ms，循環(huán)20次實現(xiàn)1s延時 TH1=(65536-50000)/256; /裝初值 TL1=(65536-50000)%256; EA=1; /開總中斷 ET1=1; /開定時器1中斷 TR1=1; /啟動定時器1 while(1) /在這里不停的對數(shù)碼管動態(tài)掃描等待中斷發(fā)生 display(shi,ge); void display(uchar shi,uchar ge)

3、/顯示子函數(shù) dula=1; P0=tableshi; /送段選數(shù)據(jù) dula=0; P0=0xff; /消影，送位選數(shù)據(jù)前關(guān)閉所有顯示，防止打開位選鎖存時 wela=1; /原來段選數(shù)據(jù)通過位選鎖存器造成混亂 P0=0xfe; /送位選數(shù)據(jù) wela=0; delayms(5); /延時 dula=1; P0=tablege; dula=0; P0=0xff; wela=1; P0=0xfd; wela=0; delayms(5); void T1_time()interrupt 3 TH1=(65536-50000)/256; /重裝初值 TL1=(65536-50000)%256; nu

4、m+; if(num=20) /20次循環(huán)，50ms20次=1s num=0; /到20次以后清零重新再計數(shù)20次 num1+; /數(shù)碼管顯示加1 if(num1=61) /數(shù)碼管顯示到60后又從01開始 num1=1; shi=num1/10; /把兩位數(shù)分離后分別送數(shù)碼管顯示十位和個位 ge=num1%10;匯編： ORG0000HAJMPMainORG 000BH/定時器0的中斷入口地址AJMPZDORG0030HMain:MOV R0,#1 /初始值從01開始 MOVR4,#20 /循環(huán)20次來實現(xiàn)1s延時 MOVDPTR,#TABLE/表頭地址送給DPTR MOVTMOD,#01H

5、/定時器0方式1定時50ms MOVTH0,#03CH /賦初值 MOVTL0,#0B0H SETBEA/開總中斷 SETBET0/開定時器0中斷 SETBTR0/啟動定時器0中斷LP1:MOVA,R0MOVB,#10DIV AB /A為整數(shù)B為余數(shù) MOVCA,A+DPTRSETBP2.7 /數(shù)碼管顯示十位MOV P0,#0FEHCLR P2.7SETBP2.6MOVP0,ACLR P2.6ACALL DELAY5MSMOVA,B /數(shù)碼管顯示個位MOVC A,A+DPTRSETBP2.7MOV P0,#0FDHCLR P2.7SETBP2.6MOVP0,ACLR P2.6ACALLDELAY5MSAJMPLP1ZD:MOVTH0,#03CH /重新賦初值MOVTL0,#0B0HDJNZ R4,LP2 /是否循環(huán)20次MOVR4,#20INCR0CJNE R0,#61,LP2MOVR0,#01LP2:RETI /中斷返回DELAY5MS: MOV R6,#5 /延時5msLOP1: MOV R5,#250LOP2: NOP NOP DJ