講座題目1、 基本語句用法講解。數(shù)據(jù)類型int，float，double,數(shù)組等；輸出語句printf,輸入語句scanf;if、else.2、 兩個(gè)數(shù)相加求和。#includevoid main()int a,b,sum;printf(“請輸入要求和的兩個(gè)數(shù)a和bn”);scanf(“%d%d”,&a,&b);sum = a + b;printf(“sum=%dn”,sum);3、 比較兩個(gè)數(shù)的大小并交換其值。#includevoid main()int a,b,temp;a = 3;b = 4;printf(“原值為：a=%d,b=%dn”,a,b);temp = a;a = b;b = temp;printf(a和b交換值后為 ：a=%d,b=%dn,a,b);4、 1+2+.+100求和。#includevoid main()int i,sum=0;for(i=1;i=100;i+)sum = sum + i;printf(“sum = %dn”,sum);5、 3位數(shù)反轉(zhuǎn)問題。#includevoid main()int begin,result;int g,s,b;printf(“請輸入一個(gè)三位數(shù)n”);scanf(“%d”,&begin);printf(“此三位數(shù)原值是：%d”,begin);g = begin % 10;s = (begin%100)/10;b = begin/100;result = g*100+s*10+b;printf(“逆序后的三位數(shù)為:%dn”,result);6、 函數(shù)、指針講解。6.1、函數(shù)（同樣以以上的求兩數(shù)和講解）#includeint add(int x, int y)int sum;sum = x + y;return sum;void main()int a,b,sum;printf(“請輸入欲求和的兩個(gè)數(shù)a和bn”);scanf(“%d%d”,&a,&b); sum = add(a,b);printf(“sum=%dn”,sum);6.2、指針簡單講解，傳地址問題比較兩數(shù)大小(變換兩數(shù)的值)。#includevoid swap(int *x,int *y)int temp;temp = *x;*x = *y;*y =temp;void main()int a,b;int *point1,*point2;printf(“請輸入a和b的值n”);scanf(“%d%d”,&a,&b);point1 = &a;point2 = &b;printf(“兩者原值為:a=%d,b=%dn”,a,b);swap(point1,point2);printf(“兩者變換后值為:a=%d,b=%dn”,a,b);7、 冒泡排序算法講解(將一下十個(gè)數(shù)按從小到大排序輸出)。#includevoid maoPao(int x10)int i,j,t;for(i=0;i9;i+)for(j=0;jxj+1)t = xj;xj = xj+1;xj+1 = t;void main()int a10=5,7,1,4,6,3,0,7,9,1;int i;for(i=0;i10;i+)printf(