PAGEPAGE4程序題1.計(jì)算1/1+1/2+1/3+….+1/100的值。代碼如下：publicclassDemo1{ publicstaticvoidmain(String[]args){ doublesum=0; doublen=1; while(n<=100){ sum+=1/n; n++; } System.out.println(sum); System.out.println("+++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}2.設(shè)計(jì)計(jì)算階乘的函數(shù)為：m(n)=n!。設(shè)計(jì)一個(gè)計(jì)算階乘的方法和相應(yīng)的類，并利用這個(gè)類計(jì)算4的階乘。代碼如下：publicclassDemo2{ publicstaticintjieCheng(intn){ if(n==1||n==0) returnn; else returnn*jieCheng(n-1); } publicstaticvoidmain(String[]args){ System.out.println(jieCheng(4)); System.out.println("++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}3.編寫一個(gè)應(yīng)用程序，可以計(jì)算result=1!+2!+…+100!。并輸出。代碼如下：publicclassDemo3{ publicstaticvoidmain(String[]args){ System.out.println(sum(100)); System.out.println("++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); } publicstaticintsum(intn){ intsum=0; while(n>=0){ sum=sum+jiecheng(n); n--; } returnsum; } publicstaticintjiecheng(intn){ if(n==1||n==0){ returnn; }else{代碼如下：publicclassDemo6{ publicstaticvoidmain(String[]args){ int[][]arr={{11,23,66,77,5},{1,23,5,66,4}, {5,6,8,9},{1,3,4}}; intsum=0; intmaxSum=0; intindexI=0; for(inti=0;i<arr.length;i++){ intj; for(j=0;j<arr[i].length;j++){ sum+=arr[i][j]; } if(sum>maxSum){ maxSum=sum; indexI=i; } System.out.println("第"+(i+1)+"行的數(shù)組之后為："+sum); } System.out.println("最大一行為:"+(indexI+1)); System.out.println("+++++++++++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}7.定義一個(gè)計(jì)算n!的類Fact，然后在主類Class1中創(chuàng)建一個(gè)對(duì)象N，求解4!的值。代碼如下publicclassDemo7{ publicstaticvoidmain(String[]args){ FactN=newFact(); System.out.println(N.jiecheng(4)); System.out.println("+++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}classFact{ publicintjiecheng(intn){ if(n==0||n==1){ returnn; }else{ returnn*jiecheng(n-1); } }}8.編寫一個(gè)教師類Teacher,要求：(1)教師類Teacher屬性有：name:String類對(duì)象，代表姓名age:int型，代表年齡sex:boolean型，代表性別（其中：true表示男，false表示女）phone:long型，代表聯(lián)系電話(2)教師類Teacher方法有：Teacher(Stringn,inta,Booleans,longp):有參構(gòu)造函數(shù)，形象表中的參數(shù)分別初始化姓名、年齡、性別和聯(lián)系電話。intgetAge():獲取年齡作為方法的返回值booleangetSex():獲取性別作為方法的返回值publicStringtoString():以姓名：聯(lián)系電話的形式作為方法的返回值。代碼如下：publicclassDemo8{ privateStringname="徐延遲";//姓名 privateintage;//年齡 privatebooleansex;//代表性別（其中：true表示男，false表示女） privatelongphone=123456;//聯(lián)系電話 publicStringgetName(){ returnname; } publicvoidsetName(Stringname){ =name; } publicintgetAge(){ returnage; } publicvoidsetAge(intage){ this.age=age; } publicbooleangetSex(){ returnsex; } publicvoidsetSex(booleansex){ this.sex=sex; } publiclonggetPhone(){ returnphone; } publicvoidsetPhone(longphone){ this.phone=phone; } publicStringtoString(){ returnname+":"+phone; } publicstaticvoidmain(String[]args){ Demo8d=newDemo8();System.out.println(d.toString()); System.out.println("+++++++++++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}9.定義一個(gè)復(fù)數(shù)類ComplexNumber，其中定義屬性來表示復(fù)數(shù)的實(shí)部和虛部，并實(shí)現(xiàn)復(fù)數(shù)的的相加和相減的基本方法publicclassDemo9{ //main方法 publicstaticvoidmain(String[]a){ Complex1b=newComplex1(2,5); Complex1c=newComplex1(3,4); System.out.println("b+c="+b.add(c).m+"i+"+b.add(c).n); System.out.println("b-c="+b.add(c).m+"i-"+b.add(c).n); System.out.println("+++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}//Complex類classComplex1{ publicdoublem; //實(shí)部 publicdoublen; //虛部 publicComplex1(doublem,doublen){ this.m=m; this.n=n; } //add publicComplex1add(Complex1c){ returnnewComplex1(m+c.m,n+c.n); } //jian publicComplex1jian(Complex1c){ returnnewComplex1(m-c.m,n-c.n); }}10.編寫一個(gè)學(xué)生類Student要求：(1)學(xué)生類Student屬性有：id：long型代表學(xué)號(hào)name：String類對(duì)象，代表姓名age：int型，代表年齡(2)學(xué)生類Student方法有：Student(longl,Stringa,intb)有參構(gòu)造函數(shù)，形參表中的參數(shù)分別初始化學(xué)號(hào)、姓名、年齡。intgetAge():獲取年齡作為方法的返回值。publicStringtoString():以姓名、學(xué)號(hào)的形式作為方法的返回值。代碼如下;publicclassDemo10{ privatelongid; privateStringname; privateintage; publiclonggetId(){ returnid; } publicvoidsetId(longid){ this.id=id; } publicStringgetName(){ returnname; } publicvoidsetName(Stringname){ =name; } publicintgetAge(){ returnage; } publicvoidsetAge(intage){ this.age=age; } publicDemo10(longid,Stringname,intage){ super(); this.id=id; =name; this.age=age; } @Override publicStringtoString(){ returnname+"、"+id; } publicstaticvoidmain(String[]args){ Demo10d=newDemo10(110,"徐延遲",23); System.out.println(d.toString()); System.out.println("+++++++++++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}11.編程從三個(gè)整數(shù)x,y,z中選出最大者。代碼如下;publicclassDemo11{ publicstaticvoidmain(String[]args){ intmax=max(155,23,88);System.out.println(max);System.out.println("++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); } publicstaticintmax(inta,intb,intc){ returnMath.max(Math.max(a,b),c); }}12.設(shè)計(jì)一個(gè)交通工具類vehicle，其數(shù)據(jù)成員包括速度speed和種類bind方法包括設(shè)置顏色setColor和取得顏色getColor，再設(shè)計(jì)一個(gè)子類Car，增加屬性passenger表示可容納旅客的人數(shù)，添加方法取得最大速度getMaxSpeed。代碼如下：packaget12;publicclassvehicle{ privateintspeed=110; privateStringkind; publicintgetSpeed(){ returnspeed; } publicvoidsetSpeed(intspeed){ this.speed=speed; } publicStringgetKind(){ returnkind; } publicvoidsetKind(Stringkind){ this.kind=kind; }}packaget12;publicclassCarextendsvehicle{ privateintpassenger; publicintgetMaxSpeed(){ returnsuper.getSpeed(); } publicstaticvoidmain(String[]args){ Carc=newCar(); System.out.println(c.getMaxSpeed()+"km/h"); System.out.println("++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}13.定義一個(gè)Point類，含有一個(gè)print方法，再定義一個(gè)類Point3d，繼承自父類Point類，并覆蓋父類的同名方法print()。在main方法中分別調(diào)用父類和子類的print().代碼如下：packaget13;publicclassPoint{ publicvoidprint(){ System.out.println("point方法"); }}packaget13;publicclassPoint3dextendsPoint{ @Override publicvoidprint(){ System.out.println("point3d"); } publicstaticvoidmain(String[]args){ Point3dp=newPoint3d(); p.print(); Pointp1=newPoint(); p1.print(); System.out.println("++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}14.定義一個(gè)shape抽象類，它包含一個(gè)抽象方法getArea(),在shape類上派生出Rectangle和Circle類，兩者都用getArea()方法計(jì)算對(duì)象的面積。定義一個(gè)測(cè)試類Test，在該類中計(jì)算半徑為2的圓的面積和寬度，高度分別為4和3的矩形的面積。代碼如下：packaget14;publicabstractclassshape{ publicabstractvoidgetArea();}packaget14;publicclassCircleextendsshape{ privateintr; privatefinaldoublePI=3.14159; publicCircle(intr){ this.r=r; } @Override publicvoidgetArea(){ doublesum=r*r*PI; System.out.println("Circleareais"+sum); }}packaget14;publicclassRectangleextendsshape{ privateinta; privateintb; publicRectangle(inta,intb){ this.a=a; this.b=b; } @Override publicvoidgetArea(){ intsum=a*b; System.out.println("Rectangleareais"+sum); }}packaget14;publicclassTest{ publicstaticvoidmain(String[]args){ Rectangler=newRectangle(4,3); r.getArea(); Circlec=newCircle(2); c.getArea(); System.out.println("++++++++++++++++++"); System.out.println("CZ04112267"); System.out.println("徐延遲"); }}15.編寫Account類模擬銀行儲(chǔ)蓄賬戶，一個(gè)儲(chǔ)蓄帳號(hào)有帳號(hào)、余額、年利息等屬性，有存款、取款、查詢方法。取款方法中，假設(shè)儲(chǔ)蓄帳號(hào)不允許透支。代碼如下;packaget15;publicclassAccount{ privatelongCardId; privateintbalance=1000;//余額 privatedoubleaccrual;//年利息 //存款 publicintdeposit(intm){ this.balance+=m; returnbalance; } //取款 publicvoidqukuan(intm){ if(this.balance<=0&&this.balance<m){ System.out.println("余額不足！"); }elseif(m<=this.balance){ this.balance-=m; System.out.println("取款成功！"); } } //查詢 publicvoidquery(){ System.out.println("余額為："+this.balance); } publicstaticvoidmain(String[]args){ Accounta=newAccount(); System.out.println("存款，余額為："+a.deposit(1000)); System.out.print("取款：100\n"); a.qukuan(100); System.out.print("查詢："); a.query(); System.out.println("++++++++++++++++++"); Sys