1、抗戰(zhàn)ACM1000A B ProblemProblem DescriptionCalculate a B .Inputeach line will contain two integers a and b . process to end of file。OutputFor each case，output A B in one line。Sample Input1 1Sample Output2# includeInt main()Int a、b；while(scanf(“% d % d”，a，b)！=EOF)printf(“% d n”，a b)；return 0；抗戰(zhàn)ACM1001Sum

2、 ProblemProblem DescriptionHey，welcome to hdoj(hangzou dianzi university online judge).In this problem，your task is to calculate sum(n)=1 2 3.n .Inputthe input will consist of a series of integers n，one integer per line。OutputFor eachcase，output sum (n) in one line，followed by a blank line . you may

3、 assume the result will be in the range of 32-bit sitSample Input1 100Sample Output1 5050# includeInt main()Int n、I、sum=0；while(scanf(“% d”，n)！=EOF)for(I=1)；I=n；I)sum=sum I；printf(“% d n n”，總計)；總計=0；return 0；抗戰(zhàn)ACM1002A B Problem IIProblem DescriptionI have a very simple problem for you。given two int

4、egers a and b，your job is to calculate the sum of a B .Inputthe first line of the input contains an integer t(1=t=20)which means the number of test cases . then t lines follow，Each line containsOutputFor each test case，you should output two lines . the first line is case # : ，# means the number of t

5、he test case . the second lllSample Input2 1 2Sample OutputCase 1: 1 2=3 Case 2:=#include#includeInt shu(char a)返回(a-0)；Int main()Char a1000，b1000；int num1001；Int n、I、j=1、al、bl、k、t；scanf(“% d”，n)；While(n -)getchar()；If(j！=1)printf(“ n”)；scanf(“% s”，a)；al=strlen(a)；scanf(“% s”，b)；bl=strlen(b)；K=(albl)？al : bl；for(I=0)；I=k；I)numI=0；t=k；for(k)；Al0bl0K-)numk=Shu(a-al)Shu(b-bl)；If(numk/10)numk-1；numk%=10；While(al0)numk-=Shu(a-al)；If(numk 1/10)numk；numk 1%=10；While(bl0)numk-=Shu(b-bl)；If(numk 1/10)numk；numk 1%=10；Printf (case360 n ，j)