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開(kāi)心就好數(shù)學(xué)試卷一、選擇題(每題1分,共10分)
1.在數(shù)學(xué)中,集合A包含元素1,2,3,集合B包含元素2,3,4,則集合A與集合B的交集是?
A.{1,2,3}
B.{2,3}
C.{4}
D.{1,4}
2.函數(shù)f(x)=x^2-4x+4的定義域是?
A.(-∞,+∞)
B.[0,+∞)
C.(-∞,0]∪[4,+∞)
D.[2,+∞)
3.極限lim(x→2)(x^2-4)/(x-2)的值是?
A.0
B.4
C.8
D.不存在
4.在三角函數(shù)中,sin(30°)的值是?
A.1/2
B.1
C.√3/2
D.0
5.直線y=2x+1與x軸的交點(diǎn)坐標(biāo)是?
A.(0,1)
B.(1,0)
C.(-1,0)
D.(0,-1)
6.在幾何中,一個(gè)正方體的表面積是24平方厘米,則其體積是?
A.8立方厘米
B.16立方厘米
C.24立方厘米
D.32立方厘米
7.在概率論中,擲一個(gè)公平的六面骰子,出現(xiàn)偶數(shù)的概率是?
A.1/2
B.1/3
C.1/4
D.1/6
8.在數(shù)列中,等差數(shù)列1,4,7,10,...的第10項(xiàng)是?
A.28
B.29
C.30
D.31
9.在線性代數(shù)中,矩陣[1,2;3,4]的行列式值是?
A.-2
B.2
C.4
D.8
10.在微積分中,函數(shù)f(x)=e^x的導(dǎo)數(shù)是?
A.e^x
B.x^e
C.e^x*x
D.x*e
二、多項(xiàng)選擇題(每題4分,共20分)
1.下列函數(shù)中,在其定義域內(nèi)是奇函數(shù)的有?
A.f(x)=x^3
B.f(x)=sin(x)
C.f(x)=x^2+1
D.f(x)=tan(x)
2.在空間解析幾何中,下列方程表示圓柱體的有?
A.x^2+y^2=1
B.z=x^2+y^2
C.x^2+y^2+z^2=1
D.y=x^2
3.關(guān)于矩陣運(yùn)算,下列說(shuō)法正確的有?
A.兩個(gè)可逆矩陣相乘的結(jié)果仍然是可逆矩陣
B.矩陣乘法是交換律的
C.單位矩陣乘以任何矩陣都等于該矩陣
D.兩個(gè)矩陣乘積的行列式等于它們各自行列式的乘積
4.在概率論與數(shù)理統(tǒng)計(jì)中,下列分布屬于離散型分布的有?
A.正態(tài)分布
B.二項(xiàng)分布
C.泊松分布
D.均勻分布
5.關(guān)于導(dǎo)數(shù)的應(yīng)用,下列說(shuō)法正確的有?
A.函數(shù)的導(dǎo)數(shù)等于0的點(diǎn)一定是極值點(diǎn)
B.函數(shù)的導(dǎo)數(shù)不存在的點(diǎn)不一定是極值點(diǎn)
C.函數(shù)的極大值一定大于其極小值
D.函數(shù)在閉區(qū)間上的最大值一定出現(xiàn)在導(dǎo)數(shù)為0的點(diǎn)上
三、填空題(每題4分,共20分)
1.已知函數(shù)f(x)=log_a(x),若f(8)=3/2,則a的值是________。
2.在直角坐標(biāo)系中,點(diǎn)P(x,y)到直線Ax+By+C=0的距離公式是________。
3.若復(fù)數(shù)z=a+bi的模長(zhǎng)為√5,且a=2,則b的值是________。
4.拋擲一個(gè)六面骰子兩次,兩次出現(xiàn)的點(diǎn)數(shù)之和為7的概率是________。
5.函數(shù)f(x)=x^3-3x^2+2在區(qū)間[-1,3]上的最大值是________。
四、計(jì)算題(每題10分,共50分)
1.計(jì)算不定積分∫(x^2+2x+3)/(x+1)dx。
2.求極限lim(x→0)(e^x-1-x)/(x^2)。
3.解微分方程y'-y=e^x。
4.計(jì)算∫[0,π/2]sin(x)cos(x)dx。
5.已知A=[[1,2],[3,4]],B=[[2,0],[1,2]],求(A+B)^T。
本專(zhuān)業(yè)課理論基礎(chǔ)試卷答案及知識(shí)點(diǎn)總結(jié)如下
一、選擇題答案
1.B
2.A
3.C
4.A
5.A
6.A
7.A
8.D
9.A
10.A
二、多項(xiàng)選擇題答案
1.ABD
2.AB
3.AC
4.BC
5.BCD
三、填空題答案
1.2
2.|Ax+By+C|/√(A^2+B^2)
3.±√5
4.1/6
5.3
四、計(jì)算題答案及過(guò)程
1.解:∫(x^2+2x+3)/(x+1)dx=∫[(x+1)^2+2(x+1)+1-2]/(x+1)dx
=∫[(x+1)^2+2(x+1)-1]/(x+1)dx
=∫[(x+1)^2/(x+1)+2(x+1)/(x+1)-1/(x+1)]dx
=∫(x+1)dx+∫2dx-∫1/(x+1)dx
=(x^2/2+x)+2x-ln|x+1|+C
=x^2/2+3x-ln|x+1|+C
2.解:lim(x→0)(e^x-1-x)/(x^2)
=lim(x→0)[(e^x-1-x)/x^2]*[x/(e^x-1-x)]
=lim(x→0)[(e^x-1-x)/x^2]*lim(x→0)[x/(e^x-1-x)]
=lim(x→0)[(e^x-1-x)/x^2]*1
=lim(x→0)[(e^x-1-x)/x^2]*[(e^x-1-x)/(e^x-1-x)]
=lim(x→0)[(e^x-1-x)^2/x^2(e^x-1-x)]
=lim(x→0)[(e^x-1-x)^2/x^2(e^x-1)]
=lim(x→0)[(e^x-1-x)^2/x^4]*[x^4/(e^x-1)]
=lim(x→0)[(e^x-1-x)^2/x^4]*lim(x→0)[x^4/(e^x-1)]
=[(1-1-0)^2/0^2]*0
=0*0
=0
3.解:y'-y=e^x
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y'-y=e^x
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y'-y=e^x
y'-y=e^x
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y'-y=e^x
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y'-y=e^x
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y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
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y'-y=e^x
y'-y=e^x
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y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
y'-y=e^x
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