1、.【連連看】簡(jiǎn)單小游戲初始源代碼使用說(shuō)明：進(jìn)入Java開(kāi)發(fā)工具eclipse 中，在左面建立一個(gè)任意名的java project, 然后在工程下建立一個(gè)名字為L(zhǎng)ianliankan 的 package，最后建立一個(gè)名字為lianliankan 的 class 類(lèi)。將以下程序代碼復(fù)制入class 內(nèi)容面板中，點(diǎn)擊運(yùn)行。package Lianliankan;import javax.swing.*;import java.awt.*;import java.awt.event.*;public class lianliankan implements ActionListenerJFrame m

2、ainFrame; / 主面板Container thisContainer;JPanel centerPanel,southPanel,northPanel; / 子面板JButton diamondsButton = new JButton65;/游戲按鈕數(shù)組JButton exitButton,resetButton,newlyButton; /退出，重列，重新開(kāi)始按鈕JLabel fractionLable=new JLabel(0); / 分?jǐn)?shù)標(biāo)簽JButton firstButton,secondButton; /分別記錄兩次被選中的按鈕int grid = new int87;/

3、儲(chǔ)存游戲按鈕位置static boolean pressInformation=false; /判斷是否有按鈕被選中int x0=0,y0=0,x=0,y=0,fristMsg=0,secondMsg=0,validateLV; / 游戲按鈕的位置坐標(biāo)int i,j,k,n;/ 消除方法控制public void init()mainFrame=new JFrame(JKJ連連看 );thisContainer = mainFrame.getContentPane();thisContainer.setLayout(new BorderLayout();centerPanel=new JPan

4、el();southPanel=new JPanel();northPanel=new JPanel();thisContainer.add(centerPanel,Center);thisContainer.add(southPanel,South);thisContainer.add(northPanel,North);centerPanel.setLayout(new GridLayout(6,5);for(int cols = 0;cols 6;cols+)for(int rows = 0;rows 5;rows+ )diamondsButtoncolsrows=new JButton

5、(String.valueOf(gridcols+1rows+1); diamondsButtoncolsrows.addActionListener(this); centerPanel.add(diamondsButtoncolsrows);exitButton=new JButton( 退出 );exitButton.addActionListener(this);resetButton=new JButton( 重列 );resetButton.addActionListener(this);newlyButton=new JButton( 再來(lái)一局 );.newlyButton.ad

6、dActionListener(this);southPanel.add(exitButton);southPanel.add(resetButton);southPanel.add(newlyButton);fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText();northPanel.add(fractionLable);mainFrame.setBounds(280,100,500,450);mainFrame.setVisible(true);public void randomBuild

7、() int randoms,cols,rows;for(int twins=1;twins=15;twins+) randoms=(int)(Math.random()*25+1);for(int alike=1;alike=2;alike+) cols=(int)(Math.random()*6+1);rows=(int)(Math.random()*5+1);while(gridcolsrows!=0) cols=(int)(Math.random()*6+1);rows=(int)(Math.random()*5+1);this.gridcolsrows=randoms;public

8、void fraction()fractionLable.setText(String.valueOf(Integer.parseInt(fractionLable.getText()+100);public void reload() int save = new int30;int n=0,cols,rows;int grid= new int87;for(int i=0;i=6;i+) for(int j=0;j=0) cols=(int)(Math.random()*6+1);rows=(int)(Math.random()*5+1);.while(gridcolsrows!=0) c

9、ols=(int)(Math.random()*6+1);rows=(int)(Math.random()*5+1);this.gridcolsrows=saven;n-;mainFrame.setVisible(false);pressInformation=false; / 這里一定要將按鈕點(diǎn)擊信息歸為初始 init();for(int i = 0;i 6;i+)for(int j = 0;j 5;j+ )if(gridi+1j+1=0)diamondsButtonij.setVisible(false);public void estimateEven(int placeX,int pl

10、aceY ,JButton bz) if(pressInformation=false) x=placeX;y=placeY;secondMsg=gridxy;secondButton=bz;pressInformation=true;else x0=x;y0=y;fristMsg=secondMsg;firstButton=secondButton;x=placeX;y=placeY;secondMsg=gridxy;secondButton=bz;if(fristMsg=secondMsg & secondButton!=firstButton)xiao();public void xia

11、o() / 相同的情況下能不能消去。仔細(xì)分析，不一條條注釋if(x0=x &(y0=y+1|y0=y-1) | (x0=x+1|x0=x-1)&(y0=y) / 判斷是否相鄰 remove();else.for (j=0;jj) / 如果第二個(gè)按鈕的 Y 坐標(biāo)大于空按鈕的 Y 坐標(biāo)說(shuō)明第一按鈕在第二按鈕左邊 for (i=y-1;i=j;i- ) / 判斷第二按鈕左側(cè)直到第一按鈕中間有沒(méi)有按鈕if (gridxi!=0) k=0;break;else k=1; /K=1 說(shuō)明通過(guò)了第一次驗(yàn)證if (k=1) linePassOne();if (yj) / 如果第二個(gè)按鈕的 Y 坐標(biāo)小于空按鈕的

12、 Y 坐標(biāo)說(shuō)明第一按鈕在第二按鈕右邊 for (i=y+1;i=j ;i+ ) / 判斷第二按鈕左側(cè)直到第一按鈕中間有沒(méi)有按鈕 if (gridxi!=0)k=0;break;else k=1; if (k=1)linePassOne();if (y=j ) linePassOne();if (k=2) if (x0=x) remove();if (x0x) for (n=x0;nx) for (n=x0;n=x+1 ;n- ) if (gridnj!=0) k=0;break;if(gridnj=0 & n=x+1) remove();for (i=0;ii) for (j=x-1;j=i

13、;j- ) if (gridjy!=0) k=0;break;else k=1; if (k=1) rowPassOne();if (xi) for (j=x+1;j=i;j+ ) if (gridjy!=0) k=0;break;else k=1; if (k=1) rowPassOne();if (x=i) rowPassOne();.if (k=2)if (y0=y) remove();if (y0y) for (n=y0;ny) for (n=y0;n=y+1 ;n-) if (gridin!=0) k=0;break;if(gridin=0 & n=y+1) remove();pub

14、lic void linePassOne()if (y0j) / 第一按鈕同行空按鈕在左邊f(xié)or (i=y0-1;i=j ;i- ) / 判斷第一按鈕同左側(cè)空按鈕之間有沒(méi)按鈕 if (gridx0i!=0) k=0;break;else k=2; /K=2 說(shuō)明通過(guò)了第二次驗(yàn)證if (y0j) / 第一按鈕同行空按鈕在與第二按鈕之間for (i=y0+1;ii) for (j=x0-1;j=i ;j- ) if (gridjy0!=0) k=0;break;else k=2; if (x0i) for (j=x0+1;j=i ;j+ ) if (gridjy0!=0) k=0;break;el

15、se k=2; public void remove()firstButton.setVisible(false);secondButton.setVisible(false);fraction();pressInformation=false;k=0;gridx0y0=0;gridxy=0;public void actionPerformed(ActionEvent e) if(e.getSource()=newlyButton)int grid = new int87;this.grid = grid;randomBuild();mainFrame.setVisible(false);pressInformation=false;init();.if(e.getSource()=exitButton)System.exit(0);if(e.getSource()=resetButton)reload();for(int cols