電子科技大學(xué)學(xué)生考試卷（05）卷考試日期：年1月日3nsin、lim。nnsinxxxf(x)dx=。d1(x)2、［=。dxx4a=(,2,1)b=)與。1)=x。t15lim(cotx0x)。sinxxy。1)＇.yx22x1（xx-。3x5x3sinxxx>0x。6x5x3x5y322xxe()。x26arctantxyy(x)2t2ytye5dy2(x)yexyeydx2x061x2y8x2和y2x122。x21811(1x)x,x0xe設(shè)f(x)(),Cfxx=0,x0C8xxe,x0(x)3(fx。設(shè)f1+x,x021atsint)yacost)x,1381(x)(,)F(x)xaft)dt(a0),f2axaF＇1limxaft)dt.2aa0xa(x)xa,xamfF(x)f(x)Mm.答()答案僅供參考2sinx21、cosxC、2x、4xx3(cotx)sinx則lnysinxlncotxy11()cotx1sinxcotxsinx2limlnylimlnlimlim0cosxcosxx0x0x0x02sinxsinx2limye0==x012x1xx112、y(()x1x2x11xx1x2122x2222()3x247374x)Cx4x23ln3(x)xsinxf(x)1xf0xf(x)0x(x)f(0)0即sinxx故fx3x2令g(x)xxg(x)x1620g(x)0g(x)g(0)0x故xx33xx0xxx，即x665533x10x3y6xy0x則y0即x、y令2355520(,)(,)(,)333270(xx)e2(xxe222exxxx20x2004ee2e22x220ye2t2yy2tyye0y則y對t:2tty)1(yet)2t2x對t1t2ty)10y1時0yeyyxy、xyx0e1eyeyyyxy0=yy2yx0e21yx224x8x或22y8x21(8xxdx8xdxxdx22222A2222000838xdx(22sin)xt20484322301x11221()2()1=x2dx2dx2x1x11212x212dx2dx2x22x1x1212122xx1222221111(1x)1x)1xx)1xxlnylnx)xy則xxexex211121xlime1x0故Ce1limlnylim故y222xx0x042xxx2由題可得：f(x(x2)e,x2(2x)f(x2)(x4x5)(x2)e3232x)1121433x2x5x(2x)de(2x)(2x)eed(2x)(2x)3221(2x)33322241172()1ee33ea(1cost)yasint1t所以Sat)a2a2222101tt2asindt4cos4a(cos1)02221同理得：S=4a(cos1)224a(cos1)S2112由題意：==cos==1S32234a(cos1)22所