A.

B.

C. A.

= B.

+3b=5 C.

÷=

b=b A.B.C. A.

B.

C.

=8=6eq

\o\ac(△,為)

eq

\o\ac(△,，則)

A.

B.

C.

=++2+4

A.

B.

C.

______ +=______

+3______

______

=

E=______

eq

\o\ac(△,，當(dāng))

______

÷

+

=EF

F

=1

BF

______

EF

（不完整）．請(qǐng)______

MN

DE

E

cm= cm

E

cmDEE

eq

\o\ac(△,Rt)

=eq

\o\ac(△,S)

=2

eq

\o\ac(△,）)

FE

=CE=

=

=h+=h= +=2+1=2+1

=2=

+1____________

=+1____________=mm

m

m

EFBEDFEFBE

BE=DFEF

BE+DF+EF=______BEDF

=4 +2=4

=+3b÷=b=b

eq

\o\ac(△,、)

==86=4

+

+1

eq

\o\ac(△,、)

+

+1

eq

\o\ac(△,=)+2

×nnnnn×n

nb+=bb+1=b+3+3

+3=2++2019=2+

+3+3

+3=2

=×÷===+=

×=+

=+

=

=

=

=

=

=

=

==

==

==

=

=

=

=

=

==

==

==

==

÷=

=1=

=1+2 -2×

+2=1+2 +2=3+ EFEDED=

DFDF=

EDDF

=ED=FD

EDED=

DFDF=

ED=FD=======+=FCB=FBC

==1FB=CFFB=FC=BCF=CBF=BCF=CF+1=1+=BF=

==1BF=CFBF=CF=

=

=AMAN

=10

..）根據(jù)

.40÷

.BE

eq

\o\ac(△,Rt)

=4

cm=

=2 cm===20cm=2cmcm

=6cmDE=

=

=2

cm

eq

\o\ac(△,Rt)

DE=2 =4 BE==6 cmE cm

BE

BE=2

=2eq

\o\ac(△,S)

=2×2=4==2eq

\o\ac(△,）)

E

=2=2=

+1

eq

\o\ac(△,S)

=2=4=2===BFD+DBF+DBF =ECB= CE=BE

=

=10BE==10×

=6=

=

=8 BE=CE=6CE==

=

eq

\o\ac(△,Rt)

= = =

=+DBF

=ECB=eq

\o\ac(△,證明)

BEBE

BE=CE=6==mm=mm

=mxm

mm

=mm

=0

=-1

=3=4+16m=1+m=9+9m+=，即

m+1+m=9+9m

m=

m=-

m

=+bm

=-mxm

mmmxm=mm+mx+m=m=m

=

×=

m

m

=

eq

\o\ac(△,時(shí)，)

m

m=

m=-2=+1=+1

= ==mm=mm

=mxm

mm

=mm

=0

=-1

=3=4+16m=1+m=9+9m+=，即

m+1+m=9+9m

m=

m=-

m

=+bm

=-mxm

mmmxm=mm+mx+m=m=m

=

×=

m

m

=

eq

\o\ac(△,時(shí)，)

m

m=

m=-2m

eq

\o\ac(△,Rt)

m

m

mm

EDBFBE=DFBEDF

EBFDEF

BEBE

=GEF=EFD

eq

\o\ac(△,Rt)

+=+EF=BE+DF+EF=2

GEFDEF=EG=DFBE+EG=2

BE+DF+EF=2

BE

BE=GEF=EFD

GEFDEF=EG=DF

eq

\o\ac(△,Rt)

+=BE+EG+EF==2BE+DF+EF=2

PE

BEPE

BE

=EPEG=

BE=EG==EG=

= =4=4