1.5#include

<stdio.h>void

main(

){printf(“******************************\n”);printf(“\n”);printf(“□□□□□□□Very

good!\n”);printf(“\n”);printf(“******************************\n”);}電信學(xué)院蔣玉蓮1第一章習(xí)題1.6方法一：#include

<stdio.h>void

main(){int

a,b,c,max;scanf(“%d,%d,%d”,&a,&b,&c);max=a;if(max<b)max=b;if(max<c)max=c;printf(“The

max

is

%d”,

max);}電信學(xué)院蔣玉蓮2方法二：#include

<stdio.h>void

main(){int

max(int

x,

int

y);int

a,b,c,d,e,f；scanf("%d,%d,%d",&a,&b,&c);d=max(a,b);e=max(a,c);f=max(d,e);printf("The

max

is

%d\n",

f);}int

max(int

x,

int

y){int

z;if

(x>y)

z=x;else

z=y;return

z;}電信學(xué)院蔣玉蓮3習(xí)題3.7電信學(xué)院蔣玉蓮4#include<stdio.h>void

main(

){char

c1=‘c’,c2=‘h’,c3=‘i’,c4=‘n’,c5=‘a(chǎn)’;c1+=4;c2+=4;c3+=4;c4+=4;c5+=4;printf(“the

cipher

is:

%c

%c

%c

%c

%c\n”,c1,c2,c3,c4,}第三章習(xí)題習(xí)題3.9(1)

x+a%3*(int)(x+y)%2/4設(shè)x=2.5,a=7,y=4.7答案為2.5電信學(xué)院蔣玉蓮5設(shè)a=2,b=3,x=3.5,y=(2)(float)(a+b)/2+(int)x%(int)y答案為3.5習(xí)題3.12(1)

a=24(2)

a=10(3)

a=60(4)

a=0(5)

a=0(6)

a=0電信學(xué)院蔣玉蓮64.4#include<stdio.h>void

main(){int

a,

b,

c;long

int

u,

n;float

x,

y,

z;char

c1,

c2;a=3;

b=4;

c=5;x=1.2;

y=2.4;

z=

-3.6;u=51274;

n=128765;c1=‘a(chǎn)’;

c2=‘b’;printf(“a=%2d□□b=%2d

□□

c=%2d

\n”,

a,

b,

c

);printf(“x=%8.6f,

y=%8.6f,

z=%9.6f\n”,

x,

y,

z);電信學(xué)院蔣玉蓮7第四章習(xí)題printf(“x+y=%5.2f

□□

y+z=%5.2f

□□z+x=%5.2f\n”,x+y,y+z,z+x);printf(“u=%6ld

□□n=%9ld\n”,u,n);printf(“c1=‘%c’

□or

□%d(ASCII)\n”,c1,c1);printf(“c2=‘%c’

□or

□%d(ASCII)\n”,c2,c2);}電信學(xué)院蔣玉蓮8習(xí)題4.8:圓半徑r=1.5，圓柱高h(yuǎn)=3，求圓周長(zhǎng)、圓面積、圓球面積、圓球體積、圓柱體積。輸出的結(jié)果取小數(shù)點(diǎn)后2位數(shù)字。#include<stdio.h>void

main(){float

pi,

h,

r,

l,

s,

sq,

vq,

vz;pi=3.1415926;

printf(“input

r,

h:\n”);scanf(“%f,%f”,

&r,

&h);電信學(xué)院蔣玉蓮9l=2*pi*r;

s=pi*r*r;vq=4.3/3.0*pi*r*r*r;sq=4*pi*r*r;vz=pi*r*r*h;printf(“the

perimeter

of

the

circle:

l=%6.2f\n”,l);printf(“the

area

of

the

circle:

s=%6.2f\n”,s);printf(“the

face

area

of

the

pallet:

sq=%6.2f\n”,sq)printf(“the

cubage

of

the

pallet:

vq=%6.2f\n”,vq);printf(“the

cubage

of

the

column:

sz=%6.2f\n”,sz);}習(xí)題4.9：#include<stdio.h>void

main(){float

c,f;printf(“input

the

fahrenheit:\n”);scanf(“%f”,

&f);c=(5.0/9.0)*(f-32);printf(“the

centigrade

:%5.2f\n”,c);}電信學(xué)院蔣玉蓮10第五章習(xí)題電信學(xué)院蔣玉蓮11習(xí)題5.3:設(shè)a=3,b=4,c=5。(1)0(2)1(3)(5)11(4)0習(xí)題5.4#include<stdio.h>void

main(){int

a,b,c;printf(“please

input

a,b,c:”);scanf(“%d,%d,%d”,&a,&b,&c);if(a<b){if(b<c)printf(“max=%d\n”,c);elseprintf(“max=%d\n”,b);}else

if

(a<c)printf(“max=%d\n”,c);elseprintf(“max=%d\n”

a);}12習(xí)題5.5#include<stdio.h>void

main(){int

x,y;printf(“please

input

x:”);scanf(“%d”,

&x);if

(x<1){

y=x;

printf(“x=%d,y=x=%d\n”,x,y);}else

if

(x<10){

y=2*x-1;

printf(“x=%d,y=

2*x-1

=%d\n”,x,y);}else{y=3*x-11;

printf(“x=%d,y=

3*x-11

=%d\n”,x,y);}}電信學(xué)院蔣玉蓮

13習(xí)題5.6#include<stdio.h>void

main(){float

score;int

grade;printf(“Input

a

score(0~100):

”);scanf(“%f”,

&score);grade

=

score/10;switch

(grade){·

case

10:·case

9:

printf(“grade=A\n”);

break;14·

case

8:

printf("grade=B\n");

break;15case

7:

printf("grade=C\n");

break;case

6:

printf("grade=D\n");

break;case

5:case

4:case

3:case

2:case

1:case

0:

printf(“grade=E\n”);}}·程序運(yùn)行情況如下：·Input

a

score(0~100):

85.5↙·grade=B電信學(xué)院蔣玉蓮習(xí)題5.7#include<stdio.h>void

main(){long

int

num;int

indiv,

ten,

hundred,

thousand,

ten_thousand,

place;scanf(“%ld”,&num);if(num>9999)place=5;else

if(num>999)place=4;else

if(num>99)place=3;else

if(num>9)place=2;elseplace=1;printf(“place=%d\n”,

place);16printf(“每位數(shù)字為：”）；ten_thousand=num/10000;thousand=(num-

ten_thousand*10000)/1000;hundred=

(num-

ten_thousand*10000-thousand*1000)/100;ten=

(num-

ten_thousand*10000-thousand*1000-hundred*10indiv=

num-

ten_thousand*10000-thousand*1000-hundred*1ten*10;17電信學(xué)院蔣玉蓮switch(place){case

5:

printf(“%d,%d,%d,%d,%d”,

ten_thousand,thousand,hundred,

ten,indiv);printf(“逆序輸出為：%d,%d,%d,%d,%d\n”,indiv,ten,hundred,

thousand,

ten_thousand);break;case

4:

printf(“%d,%d,%d,%d”,

thousand,

hundred,ten,indiv);printf(“逆序輸出為：%d,%d,%d,%d\n”,indiv,tenhundred,thousand);break;case

3:printf(“%d,%d,%d”,hundred,ten,indiv);printf(“逆序輸出為：%d,%d,%d\n”,indiv,ten,hundred);break;case

2:

printf(“%d,%d”,

ten,indiv);printf(“逆序輸出為：%d,%d\n”,indiv,ten);breacase

1:

printf(“%d”,

indiv);}}18printf(“逆序輸出為：%d\n”,indiv);電信學(xué)院蔣玉蓮習(xí)題5.8

用if編程實(shí)現(xiàn)#include<stdio.h>void

main(){long

i;float

bonus,bon1,bon2,bon4,bon6,bon10;bon1=100000*0.1;bon2=bon1+100000*0.075;bon4=bon2+200000*0.05;bon6=bon4+200000*0.03;bon10=bon6+400000*0.015;printf(“please

input

the

profit:”);scanf(“%ld”,&i);電信學(xué)院蔣玉蓮19if

(i<=100000)bonus=i*0.1;else

if

(i<=200000)bonus=bon1+(i-100000)*0.075;else

if

(i<=400000)bonus=bon2+(i-200000)*0.05;else

if

(i<=600000)bonus=bon4+(i-400000)*0.03;else

if

(i<=1000000)bonus=bon6+(i-600000)*0.015;elsebonus=bon10+(i-1000000)*0.01;printf(“bonus=%f”,bonus);}電信學(xué)院蔣玉蓮20習(xí)題5.9#include<stdio.h>void

main(){int

a,b,c,d,t;printf(“please

input

a,b,c,d:”);scanf(“%d,%d,%d,%d”,

&a,

&