精選文庫答案僅供參考1、 改錯題1. 找出以下兩處邏輯錯誤（非編程規(guī)范）并改正 char* getErrorString(int errcode)char errorString = not exist; char errorString2 = not available;switch(errcode) case 1: return errorString; case 2: return errorString2; default: return NULL;void printErrorString(int errcode)char *errorString = getErrorString(errcode);printf(errcode:%d, errorString:%sn, errcode, errorString); case1和case2返回了兩個局部變量指針，而局部變量在函數結束后將自動釋放。改正：將字符數組改為指針 char *errorString= not exist; char *errorString2 = not available;2. 以下是輸出“welcome home”的程序，找出邏輯錯誤（非編程規(guī)范）并改正 const int MAX_STR_SIZE = 12; int main(int argc, char *argv) char strMAX_STR_SIZE; strcpy(str,welcome home); printf(%s, str);return 0; “welcome home”字符串應該是13個字節(jié)，而str字符數組只能存儲12個字符 改正： const int MAX_STR_SIZE = 13;2、 程序填空題1. 寫出String類的構造函數，析構函數和賦值函數 class Stringpublic:String(const char *str = NULL);String(const String &other);String();String& operator =(const String &other);private:char *m_data;String:String()(1)delete m_data;String:String(const char *str)if( (2)str=NULL ) m_data = (3)new char;*m_data = 0;else int length = (4)strlen(str);m_data = new charlength+1;strcpy(m_data, str);String& String:operator =(const String &other)if( (5) this = other) return (6)*this;(7) delete m_data;int length = strlen( (8)other );m_data = new charlength+1;(9)strcpy(m_data,other.m_data)return (10)*this;2. 一個計算到指定年份有多少個“黑色星期五”（當月的13號并且是星期五)的程序，具體忘了。3、 編程題1. 實現以下函數，把給定string中的和替換成(和)std:string replace(std:string &str) for(int i = 0; i 0) acount+=num%B; /保存余數 num=num/B; for(int i = count - 1; i =0; i-