K

vp=p

V^=0

VxH=J+^

V(ExH)=(Vx￡)H-(VxH)-E

/?0=+/?vx5)-v=pv

E=(VxH-——

__60-

=[-V.(EX//)+(VXE)-H]--^.E

H

--------

——Qyv

—▽?s=f?E+

dt

\S-d&=￡fV+[wdV

2

(Poynting)

0

2.

E=-▽?D=QV-=^EE+^E=-VS

V2^?+—V^-V^=-p

w=°，

V2<p=-pf/s

0(poisson)

0,0,0

3.

2i

Z)=

=-V

+f

0=-[V?(Q)

-f

V.(^5)JV+f

Jx

Joe

Jx

Joe

Joe

Joe

W=-\^p(pdV

(1)

1

(2)2

(3)

w'=L^yf

4.

o

VB=O,B=VxA

VxH=J,

B)=V

H

P+VB=V?(▽x2)+

“““““

\7x

=V—?(VxA)+—[V(V?A)-V2A]=7

=0,

(Vx

=0

V2A=-pJ

(V.A=0)

A7

111V—=0

5.

V—?(VxA)=0_

V(Ax//)=(VxA)H-(Vx//).A＞

B=VxA,

5-J?=(VxA)-j?=V.(AxH)+A-(VxH)=V.(AxH)+A

(1)

1

(2)

(3)

2

"Vo

6.

=o

b

VxH=O

V-B=O

V//=-VM

(1)

(2)

Px=0....................................(1)

(2)

0,”

0”

7.

(0/=0,=0)

V0..........................................................(1)

Vx￡=

VE=0..............

()0

VxB=//5—

Vx(VxE)=V(VE)-V2E,Vx(VxB)=V(V

(3)(4)

Vx(VxE)=-^(V

7-

(4)

(2)

Q)

(.4)

(2)

(1)

v(<^)=

8?

=E(x)exp(—Zey

=B(x)exp(—/d?

v?E=o.............(1)

VxE=……“.....(

2)

⑶

VxB=

(2)

E

(1)(4)

Vx(Vx￡)=x

V(VE)-V2E=

V2E+G)2JLJSE=O

V2E+it2E=O

(V?￡=0)

(4)

V

2

(2)(3)

+

(2)

V2BJ12B=0

(VB=0)

E=—!—Vx^

(4)

o

(1)

(2)

E(x)exp(—zTy

B(x)exp(-z7y

a

?

1

V2E-=o

7

1

V2B-

V2E+Jt2￡=O

V2B+Jt2B=O

(Helmholtz)

9.

=Eoexp[KR-x—6?/)]

a

V.￡=0

VxE=-—

V5=0

...................................................⑴

V

"=0 (

3)

(

4)

(1)(3)E(2)()

4

1

CD

-

V

EB=-E(/?xE)=0

v

E(TEM)

E

EB

E

(1)

E=VB

Q

O=V{Eoexp[K

VxE=z^x￡,

Eo.Vexp

V^ik

E=VB=-^B

(2)

2

w

=-LB2=W_

IU

2"

10.

E

VE=

V?

V

a

p=pQexp(__t)

8

0

11?

z

E(z,r)=Eoexp(-az)exp[z(/7

v-5=o (1

)

VxE=-—— (

2)

VB=O (

3)

W7+ (

4)

(2)

H=—PxE=—(/?+ia)e.xE=—7/?2+?2exp((0/d

-)e.xEp

0>°,0

04

4

exp7

4*

exp

9

TEM

1

1);

(3)

12.

fVB=0..................................................

Vx￡=-—

▽?￡=2....^0

.(1)

(3)

00()--..

Vx5=//J+//^

(2)

(4)

(5)

(4)

Vx(VxA)=z/0J+￡()“o

V(V-A)-V2A=/Z07

0^￥—￡()"o-|-

T

r

—

V7”71V7/V771O0\7(6)

VA-——^-￥(7^+——)=-/V

=1/(“(J

(5)(3)

▽w+—(7)

—

(6)⑺

51dA7

_

21

P

C0

(dJAlembert)

13.

E)1/R

VT2’

x4

44

5=-Re(E*x^)=—Re|(B*xH)xBl=—B2n

22“2o

P=￡lSk/L

_(1)

Z

—likRlsin&￡4R

&

ikR1Isin&

E0

1——

2

5=—

2"

F=fJ§=(I§Hsin0

IpPf.3q1I^P

=——9sin

324o3c

(2)

R

xl/Hsin?&

PXR

14.

V-B=0 ”?(

1)

VxE=-_ ⑵

V-E=Q/ (

3)

▽x3/AQJ(

4)

L

(3)(4)

—*—*—?—?I—?

/=/?￡+JxZ?=[^0(V.￡)]￡+(VxB-^0)x3ZA)&

1-

VxB)xB-^()

ZA)&_

(1)(2)

1

+—(▽x3)xB—

_

"o&

+—(VB)B+6-0l(Vx￡)+

"odt

(V?

+—"()?

+—(VXB)XB+^()(VXE)X

“o

xB+Ex——)

=V-[^0(EE-1ZE2)+-1-(ExB)

2“o2

T=-s^EE—“-o2+B(1))

g=8QExS

1-

(1)

w

_

(2)

(3)

c

15.

X

(K)

—

?0‘

0

0

0

1

0

0

0

0

1

0

V

0

0

ZXX

—sin^

CD